
Let \[f:{R^ + } \to R\] , where \[{R^ + }\] is the set of all positive real numbers, be such that \[f\left( x \right) = {\log _e}x\] Determine Whether \[f\left( {xy} \right) = f\left( x \right) + f\left( y \right)\] holds.
Answer
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Hint: Here a simple function is given, we need to find out whether the equation for the function $f$ holds or not. For that, we have to map the function $f$ from \[{R^ + }\]to \[R\] . The function $f$ is defined, we just need to put $xy$ in the mapping then we can find the required solution. We will get the required result.
Formula used:
Logarithm formula is defined as,
\[{\log _a}\left( {bc} \right) = {\log _a}b + {\log _a}c\]
Complete step by step answer:
It is given that, \[f:{R^ + } \to R\] , where \[{R^ + }\] is the set of all positive real numbers, be such that
\[f\left( x \right) = {\log _e}x\]
We need to find out whether \[f\left( {xy} \right) = f\left( x \right) + f\left( y \right)\] holds or not.
For that, now we are going to put $xy$ in the defined function $f$ we get,
\[f\left( {xy} \right) = {\log _e}\left( {xy} \right)\]
Since, we know that, \[{\log _a}\left( {bc} \right) = {\log _a}b + {\log _a}c\]
\[ \Rightarrow {\log _e}x + {\log _e}y\]
By using the function \[f\left( {xy} \right) = {\log _e}\left( {xy} \right)\]
\[ \Rightarrow f\left( x \right) + f\left( y \right)\]
Thus, the equation \[f\left( {xy} \right) = f\left( x \right) + f\left( y \right)\] holds.
Hence, the correct answer is option (B).
Note:
Function: A function \[f:X \to Y\] is a process or a relation that associates each element x of a set X, the domain of the function to a single element y of another set Y (possibly the same set), the codomain of the function.
If the function is called f, this relation is denoted by \[y = f\left( x \right)\] where the elements x is the argument or input of the function and y is the value of the function or output or the image of x by f.
Logarithm: In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a given number x is the exponent to which another fixed number, the base b, must be raised, to produce that number x.
The logarithm of x to base b is denoted as \[{\log _b}x\] .
Formula used:
Logarithm formula is defined as,
\[{\log _a}\left( {bc} \right) = {\log _a}b + {\log _a}c\]
Complete step by step answer:
It is given that, \[f:{R^ + } \to R\] , where \[{R^ + }\] is the set of all positive real numbers, be such that
\[f\left( x \right) = {\log _e}x\]
We need to find out whether \[f\left( {xy} \right) = f\left( x \right) + f\left( y \right)\] holds or not.
For that, now we are going to put $xy$ in the defined function $f$ we get,
\[f\left( {xy} \right) = {\log _e}\left( {xy} \right)\]
Since, we know that, \[{\log _a}\left( {bc} \right) = {\log _a}b + {\log _a}c\]
\[ \Rightarrow {\log _e}x + {\log _e}y\]
By using the function \[f\left( {xy} \right) = {\log _e}\left( {xy} \right)\]
\[ \Rightarrow f\left( x \right) + f\left( y \right)\]
Thus, the equation \[f\left( {xy} \right) = f\left( x \right) + f\left( y \right)\] holds.
Hence, the correct answer is option (B).
Note:
Function: A function \[f:X \to Y\] is a process or a relation that associates each element x of a set X, the domain of the function to a single element y of another set Y (possibly the same set), the codomain of the function.
If the function is called f, this relation is denoted by \[y = f\left( x \right)\] where the elements x is the argument or input of the function and y is the value of the function or output or the image of x by f.
Logarithm: In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a given number x is the exponent to which another fixed number, the base b, must be raised, to produce that number x.
The logarithm of x to base b is denoted as \[{\log _b}x\] .
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