Answer
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Hint: The domain of a function is the set of all values for which the function is defined. The range of the function is the set of all values that f outputs. Use the definition to find the range of the given function.
Complete step-by-step answer:
A function is a relation from a set of inputs to a set of possible outputs where each input is related to one and only one output.
A function defined on all real numbers is called a real function.
We are given the function \[f = \left\{ {\dfrac{{{x^2}}}{{1 + {x^2}}}:x \in R} \right\}\] defined on real numbers, hence, it is a real function.
The domain of a function is the set of all values for which the function is defined. The range of the function is the set of all values that f outputs.
We need to find the range of \[f = \left\{ {\dfrac{{{x^2}}}{{1 + {x^2}}}:x \in R} \right\}\].
For all real number x, we have:
\[1 > 0\]
Adding \[{x^2}\] to both the sides, we have:
\[{x^2} + 1 > {x^2} \geqslant 0\]
Now we divide all the three terms by \[{x^2} + 1\] which is a positive number, hence, the inequality is retained.
\[1 > \dfrac{{{x^2}}}{{{x^2} + 1}} \geqslant 0\]
Hence, we have the range of the function as \[[0,1)\].
Note: You can also find the range of the number by substituting the values in the domain and see what is the range of the results you get.
Complete step-by-step answer:
A function is a relation from a set of inputs to a set of possible outputs where each input is related to one and only one output.
A function defined on all real numbers is called a real function.
We are given the function \[f = \left\{ {\dfrac{{{x^2}}}{{1 + {x^2}}}:x \in R} \right\}\] defined on real numbers, hence, it is a real function.
The domain of a function is the set of all values for which the function is defined. The range of the function is the set of all values that f outputs.
We need to find the range of \[f = \left\{ {\dfrac{{{x^2}}}{{1 + {x^2}}}:x \in R} \right\}\].
For all real number x, we have:
\[1 > 0\]
Adding \[{x^2}\] to both the sides, we have:
\[{x^2} + 1 > {x^2} \geqslant 0\]
Now we divide all the three terms by \[{x^2} + 1\] which is a positive number, hence, the inequality is retained.
\[1 > \dfrac{{{x^2}}}{{{x^2} + 1}} \geqslant 0\]
Hence, we have the range of the function as \[[0,1)\].
Note: You can also find the range of the number by substituting the values in the domain and see what is the range of the results you get.
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