Answer
Verified
394.2k+ views
Hint: To solve this question, what we will do is first we will write the given quadratic equation ${{x}^{2}}-6x-2=0$ in terms of $\alpha $ and $\beta $. Then, we will multiply both the equations with factor ${{\alpha }^{8}}$ and ${{\beta }^{8}}$ respectively. Then we will arrange the equations together in such a way that we get factors of the same power separately and hence, we will try to get the condition asked in question.
Complete step-by-step answer:
As in question it is clearly given that, $\alpha $ and $\beta $ be the roots of equation ${{x}^{2}}-6x-2=0$ .
then, we can put x = $\alpha $ and x = $\beta $,
so, putting x = $\alpha $ in ${{x}^{2}}-6x-2=0$, we get
${{\alpha }^{2}}-6\alpha -2=0$…..( i )
so, putting x = $\beta $ in ${{x}^{2}}-6x-2=0$, we get
${{\beta }^{2}}-6\beta -2=0$…. ( ii )
Multiplying equation ( i ) by ${{\alpha }^{8}}$, we get
${{\alpha }^{8}}({{\alpha }^{2}}-6\alpha -2)=0({{\alpha }^{8}})$
$({{\alpha }^{10}}-6{{\alpha }^{9}}-2{{\alpha }^{8}})=0$
${{\alpha }^{10}}=6{{\alpha }^{9}}+2{{\alpha }^{8}}$……( iii )
Multiplying equation ( i ) by ${{\beta }^{8}}$, we get
${{\beta }^{8}}({{\beta }^{2}}-6\beta -2)=0({{\beta }^{8}})$
$({{\beta }^{10}}-6{{\beta }^{9}}-2{{\beta }^{8}})=0$
${{\beta }^{10}}=6{{\beta }^{9}}+2{{\beta }^{8}}$…..( iv )
Subtracting ( iv ) from ( iii ), we get
${{\alpha }^{10}}-{{\beta }^{10}}=6{{\alpha }^{9}}+2{{\alpha }^{8}}-(6{{\beta }^{9}}+2{{\beta }^{8}})$
On simplifying we get
${{\alpha }^{10}}-{{\beta }^{10}}=6({{\alpha }^{9}}-{{\beta }^{9}})+2({{\alpha }^{8}}-{{\beta }^{8}})$
As, in question it is given that ${{a}_{n}}={{\alpha }^{n}}-{{\beta }^{n}}$, so ${{a}_{9}}={{\alpha }^{9}}-{{\beta }^{9}}$and ${{a}_{10}}={{\alpha }^{10}}-{{\beta }^{10}}$ and ${{a}_{8}}={{\alpha }^{8}}-{{\beta }^{8}}$
${{a}_{10}}=6({{a}_{9}})+2({{a}_{8}})$
Moving, $2({{a}_{8}})$ from right hand side to left hand side, we get
${{a}_{10}}-{{a}_{8}}=6{{a}_{9}}$
Re – writing above equation, we get
${{a}_{10}}-{{a}_{8}}=3\cdot 2{{a}_{9}}$
Using cross-multiplication, we get
$\dfrac{{{a}_{10}}-{{a}_{8}}}{2{{a}_{9}}}=3$
So, the correct answer is “Option A”.
Note: Always remember if it is given that a and b are roots of quadratic equation, then we can replace x in quadratic equation with a and b. This question is a bit tricky so what you can do in this type of question is just try to re – arrange the quadratic equation according to the given equation in question to prove or any condition provided this will make the question a bit easier. Try to avoid silly mistakes as it may make the question incorrect.
Complete step-by-step answer:
As in question it is clearly given that, $\alpha $ and $\beta $ be the roots of equation ${{x}^{2}}-6x-2=0$ .
then, we can put x = $\alpha $ and x = $\beta $,
so, putting x = $\alpha $ in ${{x}^{2}}-6x-2=0$, we get
${{\alpha }^{2}}-6\alpha -2=0$…..( i )
so, putting x = $\beta $ in ${{x}^{2}}-6x-2=0$, we get
${{\beta }^{2}}-6\beta -2=0$…. ( ii )
Multiplying equation ( i ) by ${{\alpha }^{8}}$, we get
${{\alpha }^{8}}({{\alpha }^{2}}-6\alpha -2)=0({{\alpha }^{8}})$
$({{\alpha }^{10}}-6{{\alpha }^{9}}-2{{\alpha }^{8}})=0$
${{\alpha }^{10}}=6{{\alpha }^{9}}+2{{\alpha }^{8}}$……( iii )
Multiplying equation ( i ) by ${{\beta }^{8}}$, we get
${{\beta }^{8}}({{\beta }^{2}}-6\beta -2)=0({{\beta }^{8}})$
$({{\beta }^{10}}-6{{\beta }^{9}}-2{{\beta }^{8}})=0$
${{\beta }^{10}}=6{{\beta }^{9}}+2{{\beta }^{8}}$…..( iv )
Subtracting ( iv ) from ( iii ), we get
${{\alpha }^{10}}-{{\beta }^{10}}=6{{\alpha }^{9}}+2{{\alpha }^{8}}-(6{{\beta }^{9}}+2{{\beta }^{8}})$
On simplifying we get
${{\alpha }^{10}}-{{\beta }^{10}}=6({{\alpha }^{9}}-{{\beta }^{9}})+2({{\alpha }^{8}}-{{\beta }^{8}})$
As, in question it is given that ${{a}_{n}}={{\alpha }^{n}}-{{\beta }^{n}}$, so ${{a}_{9}}={{\alpha }^{9}}-{{\beta }^{9}}$and ${{a}_{10}}={{\alpha }^{10}}-{{\beta }^{10}}$ and ${{a}_{8}}={{\alpha }^{8}}-{{\beta }^{8}}$
${{a}_{10}}=6({{a}_{9}})+2({{a}_{8}})$
Moving, $2({{a}_{8}})$ from right hand side to left hand side, we get
${{a}_{10}}-{{a}_{8}}=6{{a}_{9}}$
Re – writing above equation, we get
${{a}_{10}}-{{a}_{8}}=3\cdot 2{{a}_{9}}$
Using cross-multiplication, we get
$\dfrac{{{a}_{10}}-{{a}_{8}}}{2{{a}_{9}}}=3$
So, the correct answer is “Option A”.
Note: Always remember if it is given that a and b are roots of quadratic equation, then we can replace x in quadratic equation with a and b. This question is a bit tricky so what you can do in this type of question is just try to re – arrange the quadratic equation according to the given equation in question to prove or any condition provided this will make the question a bit easier. Try to avoid silly mistakes as it may make the question incorrect.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Define absolute refractive index of a medium
Find out what do the algal bloom and redtides sign class 10 biology CBSE
Prove that the function fleft x right xn is continuous class 12 maths CBSE
Trending doubts
State the differences between manure and fertilize class 8 biology CBSE
Why are xylem and phloem called complex tissues aBoth class 11 biology CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
What would happen if plasma membrane ruptures or breaks class 11 biology CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What precautions do you take while observing the nucleus class 11 biology CBSE
What would happen to the life of a cell if there was class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE