
What is the largest $3$ digit multiple of $7$ ?
Answer
474.6k+ views
Hint: Here, we are asked to calculate the largest three-digit multiple of the number $7$. We know that the largest three-digit number is $999$. So, we shall start with $999$. When we divide the largest digit by seven, we need to get the remainder zero. If we didn’t get zero, we need to proceed by using the next largest-three digit number.
Complete answer:
We know that the largest three-digit number is $999$.
Now, we need to find the largest three-digit multiple of $7$.
a) First, we shall divide the largest three-digit number $999$ by $7$.
$7\mathop{\left){\vphantom{1
999
\underline 7
29
\underline {28}
019
\underline {14}
05
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
999
\underline 7
29
\underline {28}
019
\underline {14}
05
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $5$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $999$ cannot be the largest $3$ digit multiple of $7$
b) Next, we shall consider the largest three-digit number $998$ .
Now, we shall divide the largest three-digit number $998$ by $7$.
$7\mathop{\left){\vphantom{1
998
\underline 7
29
\underline {28}
018
\underline {14}
04
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
998
\underline 7
29
\underline {28}
018
\underline {14}
04
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $4$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $998$ cannot be the largest $3$ digit multiple of $7$
c) Next, we shall consider the largest three-digit number $997$ .
Now, we shall divide the largest three-digit number $997$ by $7$.
$7\mathop{\left){\vphantom{1
997
\underline 7
29
\underline {28}
017
\underline {14}
03
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
997
\underline 7
29
\underline {28}
017
\underline {14}
03
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $3$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $997$ cannot be the largest $3$ digit multiple of $7$
d) Next, we shall consider the largest three-digit number $996$ .
Now, we shall divide the largest three-digit number $996$ by $7$.
$7\mathop{\left){\vphantom{1
996
\underline 7
29
\underline {28}
016
\underline {14}
02
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
996
\underline 7
29
\underline {28}
016
\underline {14}
02
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $2$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $996$ cannot be the largest $3$ digit multiple of $7$
e) Next, we shall consider the largest three-digit number $995$ .
Now, we shall divide the largest three-digit number $995$ by $7$.
$7\mathop{\left){\vphantom{1
995
\underline 7
29
\underline {28}
015
\underline {14}
01
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
995
\underline 7
29
\underline {28}
015
\underline {14}
01
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $1$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $995$ cannot be the largest $3$ digit multiple of $7$
f) Next, we shall consider the largest three-digit number $994$ .
Now, we shall divide the largest three-digit number $994$ by $7$.
$7\mathop{\left){\vphantom{1
994
\underline 7
29
\underline {28}
014
\underline {14}
0
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
994
\underline 7
29
\underline {28}
014
\underline {14}
0
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $0$.
Since we get the remainder zero, $994$ is the largest $3$ digit multiple of $7$
Note:
We can also calculate the required answer by using another method. Here, let us consider the largest-three digit number$999$. When we divide the largest three-digit number by $7$, we got the remainder $5$ . We shall subtract $999$ and $5$
Thus, $999 - 5 = 994$ . Hence we got the required answer.
Complete answer:
We know that the largest three-digit number is $999$.
Now, we need to find the largest three-digit multiple of $7$.
a) First, we shall divide the largest three-digit number $999$ by $7$.
$7\mathop{\left){\vphantom{1
999
\underline 7
29
\underline {28}
019
\underline {14}
05
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
999
\underline 7
29
\underline {28}
019
\underline {14}
05
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $5$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $999$ cannot be the largest $3$ digit multiple of $7$
b) Next, we shall consider the largest three-digit number $998$ .
Now, we shall divide the largest three-digit number $998$ by $7$.
$7\mathop{\left){\vphantom{1
998
\underline 7
29
\underline {28}
018
\underline {14}
04
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
998
\underline 7
29
\underline {28}
018
\underline {14}
04
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $4$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $998$ cannot be the largest $3$ digit multiple of $7$
c) Next, we shall consider the largest three-digit number $997$ .
Now, we shall divide the largest three-digit number $997$ by $7$.
$7\mathop{\left){\vphantom{1
997
\underline 7
29
\underline {28}
017
\underline {14}
03
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
997
\underline 7
29
\underline {28}
017
\underline {14}
03
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $3$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $997$ cannot be the largest $3$ digit multiple of $7$
d) Next, we shall consider the largest three-digit number $996$ .
Now, we shall divide the largest three-digit number $996$ by $7$.
$7\mathop{\left){\vphantom{1
996
\underline 7
29
\underline {28}
016
\underline {14}
02
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
996
\underline 7
29
\underline {28}
016
\underline {14}
02
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $2$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $996$ cannot be the largest $3$ digit multiple of $7$
e) Next, we shall consider the largest three-digit number $995$ .
Now, we shall divide the largest three-digit number $995$ by $7$.
$7\mathop{\left){\vphantom{1
995
\underline 7
29
\underline {28}
015
\underline {14}
01
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
995
\underline 7
29
\underline {28}
015
\underline {14}
01
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $1$ .
But we need the remainder zero. Since we didn’t get the remainder zero, $995$ cannot be the largest $3$ digit multiple of $7$
f) Next, we shall consider the largest three-digit number $994$ .
Now, we shall divide the largest three-digit number $994$ by $7$.
$7\mathop{\left){\vphantom{1
994
\underline 7
29
\underline {28}
014
\underline {14}
0
}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{
994
\underline 7
29
\underline {28}
014
\underline {14}
0
}}}
\limits^{\displaystyle \,\,\, {142}}$
When we divide the largest three-digit number by $7$, we got the remainder $0$.
Since we get the remainder zero, $994$ is the largest $3$ digit multiple of $7$
Note:
We can also calculate the required answer by using another method. Here, let us consider the largest-three digit number$999$. When we divide the largest three-digit number by $7$, we got the remainder $5$ . We shall subtract $999$ and $5$
Thus, $999 - 5 = 994$ . Hence we got the required answer.
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