How do you know which rule of differentiation to use?
Answer
573.3k+ views
Hint: Differentiation is the process of determining the derivation of a given function. There are different rules of differentiation used to solve the derivation. But here, I explain a few rules with an example: derivation is mentioned in the following.
Complete step by step solution:
General rule for differentiation,
\[\dfrac{d}{{dx}}[{x^n}] = n{x^{n - 1}}\], Where \[n \in R\;,n \ne 0.\]
The derivative of constant is zero,
\[\dfrac{d}{{dx}}[k] = 0\]
The derivative of a constant multiplied by a function is equal to the constant multiplied by the derivative of the function,
\[\dfrac{d}{{dx}}[k \cdot f(x)] = k\dfrac{d}{{dx}}[f(x)]\]
The derivative of a sum is equal to the sum of the derivatives,
\[\dfrac{d}{{dx}}[f(x) + g(x)] = \dfrac{d}{{dx}}[f(x)] + \dfrac{d}{{dx}}[g(x)]\]
The derivative of a difference is equal to the difference of the derivatives,
\[\dfrac{d}{{dx}}[f(x) - g(x)] = \dfrac{d}{{dx}}[f(x)] - \dfrac{d}{{dx}}[g(x)]\]
Some important rules are given the following,
Simple rule, \[f(x) = xdx = 1\]
Product rule, \[f(x) = - 4xdx = - 4\]
Power rule, \[f(x) = {x^2}dx = 2x\]
Chain rule, \[\dfrac{d}{{dx}}[f(g(x))] = f\prime (g(x))g\prime (x)\]
Example: Find the derivation of the function\[y = 2\sqrt x - 3\sin x\].
By using basic differentiation rule,
$
y\prime (x) = (2\sqrt x - 3sinx)\prime \\
\Rightarrow(2\sqrt x )\prime - (3sinx)\prime \\
\Rightarrow 2(\sqrt x )\prime - 3(sinx)\prime \\
\Rightarrow 2 \cdot \dfrac{1}{{2\sqrt x }} - 3cosx \\
= \dfrac{1}{{\sqrt x }} - 3cosx. \\
$
Hence, the final answer is found.
Note: One useful thing to keep in mind is that the derivative of a sum is the sum of the derivatives, so if you have more terms you can differentiate them one by one. The things you'll meet more often are powers of a function and most of all composed of functions. An example of the first may be\[\cos 2(x)\], an example of the second \[\log (2x)\] Of course both things could happen at the same time \[sin2{\text{ }}(4x + 2)\].However, differentiation in general way, you differentiate the outer content, and then the inner one, applying the basic rules for fundamental functions.
Complete step by step solution:
General rule for differentiation,
\[\dfrac{d}{{dx}}[{x^n}] = n{x^{n - 1}}\], Where \[n \in R\;,n \ne 0.\]
The derivative of constant is zero,
\[\dfrac{d}{{dx}}[k] = 0\]
The derivative of a constant multiplied by a function is equal to the constant multiplied by the derivative of the function,
\[\dfrac{d}{{dx}}[k \cdot f(x)] = k\dfrac{d}{{dx}}[f(x)]\]
The derivative of a sum is equal to the sum of the derivatives,
\[\dfrac{d}{{dx}}[f(x) + g(x)] = \dfrac{d}{{dx}}[f(x)] + \dfrac{d}{{dx}}[g(x)]\]
The derivative of a difference is equal to the difference of the derivatives,
\[\dfrac{d}{{dx}}[f(x) - g(x)] = \dfrac{d}{{dx}}[f(x)] - \dfrac{d}{{dx}}[g(x)]\]
Some important rules are given the following,
Simple rule, \[f(x) = xdx = 1\]
Product rule, \[f(x) = - 4xdx = - 4\]
Power rule, \[f(x) = {x^2}dx = 2x\]
Chain rule, \[\dfrac{d}{{dx}}[f(g(x))] = f\prime (g(x))g\prime (x)\]
Example: Find the derivation of the function\[y = 2\sqrt x - 3\sin x\].
By using basic differentiation rule,
$
y\prime (x) = (2\sqrt x - 3sinx)\prime \\
\Rightarrow(2\sqrt x )\prime - (3sinx)\prime \\
\Rightarrow 2(\sqrt x )\prime - 3(sinx)\prime \\
\Rightarrow 2 \cdot \dfrac{1}{{2\sqrt x }} - 3cosx \\
= \dfrac{1}{{\sqrt x }} - 3cosx. \\
$
Hence, the final answer is found.
Note: One useful thing to keep in mind is that the derivative of a sum is the sum of the derivatives, so if you have more terms you can differentiate them one by one. The things you'll meet more often are powers of a function and most of all composed of functions. An example of the first may be\[\cos 2(x)\], an example of the second \[\log (2x)\] Of course both things could happen at the same time \[sin2{\text{ }}(4x + 2)\].However, differentiation in general way, you differentiate the outer content, and then the inner one, applying the basic rules for fundamental functions.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

Difference between physical and chemical change class 11 chemistry CBSE

How do I convert ms to kmh Give an example class 11 physics CBSE

What is the atomic mass of Sodium a 22 gmol b 23 gmol class 11 chemistry CBSE

In which country Lascaux cave is located A India B class 11 social science CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

