Question

What is the kinetic energy of the object of mass $100g$ moving with speed of $1m{s^{ - 1}}.$

Answer 1

Hint: In order to get the solution of this question, we need to use the formula of kinetic energy directly. Then we need to solve the equation to get the required solution of the given question. Also, we know that kinetic energy of a body is the energy when the body is in motion. We can use the formula for kinetic energy, i.e. $K.E. = \dfrac{1}{2}m{v^2}$ to get the required value.

Complete step by step solution:
As, in the question, the mass of the object is given as, $m = 100g$=$\dfrac{{100}}{{1000}}kg$
And the speed by which it is moving is given as, $v = 1m{s^{ - 1}}$
Now, we know that the kinetic energy of a body is given by, $K.E. = \dfrac{1}{2}m{v^2}$
We need to put the values of mass and velocity in the above equation to get the required solution.
So, we get, $K.E. = \dfrac{1}{2} \times \dfrac{{100}}{{1000}} \times {1^2}$
$ \Rightarrow K.E. = \dfrac{1}{{20}}$
$\therefore K.E. = 0.05J$

Hence, the required kinetic energy of the object is $0.05J$.

Note: Kinetic energy is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. The kinetic energy of a body is the energy that it possesses due to its motion. The body maintains this kinetic energy unless its speed changes. It is given by the equation, $K.E. = \dfrac{1}{2}m{v^2}$. On the other hand potential energy is the energy that is stored inside a body. The stored energy is based on the position, arrangement or state of the object. An object possesses gravitational potential energy if it is positioned at a height above the zero height. It is given by$mgh$.