How many kilograms of water must be evaporated from 40kg of a 10% salt solution to produce a 25% solution?
Answer
605.7k+ views
Hint: In the above question, it is asked how much kilograms of water needs to be evaporated from 40kg so that the salt concentration changes from 10% to 25%. Here, since, the water has evaporated, the concentration of salt is constant. So, first we have to find the concentration of salt from the 40kg then we have to find the concentration of solution when 25% salt is present. Then, by subtracting the mass of salt from the solution, we can get the amount of water that needs to be evaporated.
Formula Used
Weight of salt = percentage of weight of solution.
Complete step by step solution
In the above question, initially 40kg of solution is present and we have to find out c
concentration of salt.
Weight of salt = 10% of weight of the solution= $\dfrac{{{{10}}}}{{{{100}}}}{{ \times 40 = 4}}$ kg.
Now, we know the weight of salt and its percentage in a solution. So, the weight of the solution which contains 25% salt can be obtained by:
Weight of salt = $\dfrac{{{{25}}}}{{{{100}}}}{{ \times }}$ Weight of solution, which implies that:
Weight of solution = $\dfrac{{{{100}}}}{{{{25}}}}{{ \times }}$Weight of salt = $\dfrac{{{{100}}}}{{{{25}}}}{{ \times 4 = 16}}$ kg
Mass of water evaporated = ${{40 - 16 = 24}}$ kg
Therefore, the weight of water that is evaporated is equal to 24kg.
Note
In these types of questions, where concentration of salt is changing without changing the amount of salt in that solution, then, we can use simple mathematics to calculate the amount of water in the latter case. And hence, mass of water evaporated can be found.
Formula Used
Weight of salt = percentage of weight of solution.
Complete step by step solution
In the above question, initially 40kg of solution is present and we have to find out c
concentration of salt.
Weight of salt = 10% of weight of the solution= $\dfrac{{{{10}}}}{{{{100}}}}{{ \times 40 = 4}}$ kg.
Now, we know the weight of salt and its percentage in a solution. So, the weight of the solution which contains 25% salt can be obtained by:
Weight of salt = $\dfrac{{{{25}}}}{{{{100}}}}{{ \times }}$ Weight of solution, which implies that:
Weight of solution = $\dfrac{{{{100}}}}{{{{25}}}}{{ \times }}$Weight of salt = $\dfrac{{{{100}}}}{{{{25}}}}{{ \times 4 = 16}}$ kg
Mass of water evaporated = ${{40 - 16 = 24}}$ kg
Therefore, the weight of water that is evaporated is equal to 24kg.
Note
In these types of questions, where concentration of salt is changing without changing the amount of salt in that solution, then, we can use simple mathematics to calculate the amount of water in the latter case. And hence, mass of water evaporated can be found.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

