Juhi sells a washing machine for Rs. 13, 500. She loses 20% in the bargain. What was the price at which she bought it?
ANSWER
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Hint: Assume the cost price to be x and then use the condition that 20% of cost price when reduced from the cost price i.e. ‘x’ you will get the selling price. By simplifying this equation you will get your final answer.
Complete step-by-step answer: As Juhi sold the washing machine at Rs. 13, 500 therefore the selling price will become, SP = Rs. 13,500 …………………………………………………… (1) We will assume the cost price of the washing machine as ‘x’, therefore CP = x ………………………………………………………………………… (2) As per the given condition, Juhi loses 20% cost while selling the washing machine i.e. when 20% of the cost price is reduced from the cost price; we will get the value of selling price. Therefore 20% of the cost price can be given as, 20% of the cost price = 20% (CP) If we put the value of equation (2) in the above equation we will get, 20% of the cost price = 20%(x) Therefore, 20% of the cost price = $\dfrac{20}{100}x$ ………………………………………………………… (3) Now, as per the condition we have mentioned earlier, if we reduce 20% of CP from CP it will give us the SP therefore we can write, CP – 20% of CP = SP If we put the values of equation (1), equation (2) and equation (3) in the above equation we will get, $x-\dfrac{20}{100}x=13500$ Taking ‘x’ common from the above equation will give, $\therefore x\left( 1-\dfrac{20}{100} \right)=13500$ If we subtract the term $-\dfrac{20}{100}$ from ‘1’ in the above equation we will get, $\therefore x\left( \dfrac{100-20}{100} \right)=13500$ By simplifying the above equation we will get, $\therefore x\left( \dfrac{80}{100} \right)=13500$ Further simplification in the above equation will give, $\therefore x\left( \dfrac{8}{10} \right)=13500$ By shifting $\dfrac{8}{10}$ on the right hand side of the equation will give, $\dfrac{20}{100}CP$ $\therefore x=\dfrac{135000}{8}$ Therefore, x = Rs. 16875 Therefore the value of the cost price of the washing machine is equal to Rs. 16875.
Note: During exam there is chance of silly mistake that you can take only $\dfrac{20}{100}$ in place of $\dfrac{20}{100}CP$ or sometimes you add this value in CP as you are in hurry, but do remember that it will lead you to the wrong answer.