Answer
351.9k+ views
Hint: Joshita is having a principal amount Rs12000 and her bank compounds the interest thrice a year at an interest rate of 15% and we need to find how much money she will have at the end of the year. To find this amount, we are going to use the formula
\[ \Rightarrow A = P\left[ {{{\left( {1 + \dfrac{r}{{100}}} \right)}^n}} \right]\]
Complete step-by-step solution:
In this question, we are given that Joshita is having a principal amount of Rs12000 and her bank compounds the interest thrice a year at an interest rate of 15% and we need to find how much money she will have at the end of the year.
Now, to find the total amount at the end of the year, we have the formula
\[ \Rightarrow A = P\left[ {{{\left( {1 + \dfrac{r}{{100}}} \right)}^n}} \right]\] - - - - - - - - - - - - - - (1)
Where, $A = $Total Amount, $P = $Principal amount, $r = $ rate of interest and $n = $time period.
Here, we have
$ P = 12000 \\
r = 15\% \\
n = 3 \\
A = ? $
Therefore, substituting these values in equation (1), we get
\[ \Rightarrow A = P\left[ {{{\left( {1 + \dfrac{r}{{100}}} \right)}^n}} \right]\]
\[\Rightarrow A = 12000\left[ {{{\left( {1 + \dfrac{{15}}{{100}}} \right)}^3}} \right] \\
\Rightarrow A = 12000\left[ {{{\left( {1 + 0.15} \right)}^3}} \right] \\
\Rightarrow A = 12000\left[ {{{\left( {1.15} \right)}^3}} \right] \\
\Rightarrow A = 12000\left[ {1.520875} \right] \\
\Rightarrow A = 18250.50 \]
Hence, Joshita will save Rs18250.50 at the year's end.
Hence, option A is the correct answer.
Note: Here, note that we are taking the value of n=3 because the interest is being compounded thrice a year. If it was given that the interest is being compounded 2 a year, then we had to take the value of n equal to 2.
\[ \Rightarrow A = P\left[ {{{\left( {1 + \dfrac{r}{{100}}} \right)}^n}} \right]\]
Complete step-by-step solution:
In this question, we are given that Joshita is having a principal amount of Rs12000 and her bank compounds the interest thrice a year at an interest rate of 15% and we need to find how much money she will have at the end of the year.
Now, to find the total amount at the end of the year, we have the formula
\[ \Rightarrow A = P\left[ {{{\left( {1 + \dfrac{r}{{100}}} \right)}^n}} \right]\] - - - - - - - - - - - - - - (1)
Where, $A = $Total Amount, $P = $Principal amount, $r = $ rate of interest and $n = $time period.
Here, we have
$ P = 12000 \\
r = 15\% \\
n = 3 \\
A = ? $
Therefore, substituting these values in equation (1), we get
\[ \Rightarrow A = P\left[ {{{\left( {1 + \dfrac{r}{{100}}} \right)}^n}} \right]\]
\[\Rightarrow A = 12000\left[ {{{\left( {1 + \dfrac{{15}}{{100}}} \right)}^3}} \right] \\
\Rightarrow A = 12000\left[ {{{\left( {1 + 0.15} \right)}^3}} \right] \\
\Rightarrow A = 12000\left[ {{{\left( {1.15} \right)}^3}} \right] \\
\Rightarrow A = 12000\left[ {1.520875} \right] \\
\Rightarrow A = 18250.50 \]
Hence, Joshita will save Rs18250.50 at the year's end.
Hence, option A is the correct answer.
Note: Here, note that we are taking the value of n=3 because the interest is being compounded thrice a year. If it was given that the interest is being compounded 2 a year, then we had to take the value of n equal to 2.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)