
How many jars each holding 1.75kg of jam can be filled from a vessel containing 100kg of jam, and how much remains?
Answer
509.1k+ views
Hint: In order to deal with this question first we have to determine the number of jars required for 1kg jam further by multiplying it by 100kg we will get the total number of jars required and at last we will calculate remaining jam by subtracting obtained kg of jam from 100kg.
Complete step by step answer:
Given that each jar holding 1.75kg of jam
Or Number of jar required for 1.75kg of jam = 1
Now we will calculate number of jar required for 1kg of jam so we have
Number of jars required for 1kg of jam $ = \dfrac{1}{{1.75}}$
Now we have to calculate it for 100kg of jam that's why
Number of jars required for 100kg of jam = 100 x (number of jars required for 1kg of jam) $ = \dfrac{{100}}{{1.75}}$
Further simplifying above equation we get
$ = \dfrac{{10000}}{{175}}$
$ = 57\dfrac{1}{7}$
Therefore, 57 jars can be filled completely, which contains $ = 1.75 \times 57 = 99.75kg$
Jam remaining in the vessel = 100kg - kg of jams filled in 57 jars
$ = 100kg - 99.75kg = 0.25kg$
Hence the required number of jars is 57 and the jam remaining in the vessel is 0.25kg.
Note:
In order to solve such types of problems, students must use the unitary method as used above for an easy solution. First we have to find the volume contained by the unit jar and further by the help of this we can proceed further. Volume is the space of three-dimensional space enclosed by a closed surface, for example the space filled or formed by a material or shape. Volume is often quantified numerically using the derived SI unit, the cubic meter.
Complete step by step answer:
Given that each jar holding 1.75kg of jam
Or Number of jar required for 1.75kg of jam = 1
Now we will calculate number of jar required for 1kg of jam so we have
Number of jars required for 1kg of jam $ = \dfrac{1}{{1.75}}$
Now we have to calculate it for 100kg of jam that's why
Number of jars required for 100kg of jam = 100 x (number of jars required for 1kg of jam) $ = \dfrac{{100}}{{1.75}}$
Further simplifying above equation we get
$ = \dfrac{{10000}}{{175}}$
$ = 57\dfrac{1}{7}$
Therefore, 57 jars can be filled completely, which contains $ = 1.75 \times 57 = 99.75kg$
Jam remaining in the vessel = 100kg - kg of jams filled in 57 jars
$ = 100kg - 99.75kg = 0.25kg$
Hence the required number of jars is 57 and the jam remaining in the vessel is 0.25kg.
Note:
In order to solve such types of problems, students must use the unitary method as used above for an easy solution. First we have to find the volume contained by the unit jar and further by the help of this we can proceed further. Volume is the space of three-dimensional space enclosed by a closed surface, for example the space filled or formed by a material or shape. Volume is often quantified numerically using the derived SI unit, the cubic meter.
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