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# Janet makes homemade dolls. Currently, she produces 23 dolls per month. If she increased her production by $18\%$, how many dolls would Janet produce each month?A.27B.32C.38D.40

Last updated date: 08th Aug 2024
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Answer
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Hint: Here in this question, we have to find how many dolls Janet will produce each month. To find this first, calculate $18\%$ of 23 by percentage simplification, for this we have to write the given percentage term into fraction form and multiply this fraction with 23 and the resultant number added with the number of original production of dolls to get the required solution.

Complete step by step solution:
Consider the data in given question:
Currently, Janet makes 23 homemade dolls per month.
We have to find if she increased her production by 18% then how many dolls she will prepare each month.
First, calculate $18\%$ of $23$
Now, we have to write the percentage term i.e., $18\%$ into the fraction.
Remember that "per" means "divided by", and "cent" means 100, so "percent" means "divided by 100" or "out of 100."
Therefore $18\%$ can be written as:
$\Rightarrow \dfrac{{18}}{{100}}$
When dealing with percent’s the word "of" means "times" or "to multiply".
Let’s consider the Resultant value i.e., number of $18\%$ in $23$ as $x$
Putting this all together we can write this equation and solve for $x$ while keeping the equation balanced:
$\Rightarrow x = \dfrac{{18}}{{100}} \times 23$
$\Rightarrow x = 0.18 \times 23$
On simplification, we get
$\Rightarrow x = 4.14$
Therefore, the number $18\%$ of $23$ is $4.14$. Then, add this value to the original value i.e., 23
$\Rightarrow 23 + 4.14$
$\Rightarrow 27.14$
On rounding off the number, we get
$\Rightarrow 27$
Hence, Janet will produce 27 dolls for each month.
Therefore, option (A) is correct.
So, the correct answer is “Option A”.

Note: Here the question is related to the percentage. By using the specific methods and rules we can convert the number. As we know that the percentage term is written as $x\% = \dfrac{x}{{100}}$ , here, marked $x$ as the total value. Using the simple arithmetic operation i.e., multiplication and division to get the required solution.