
IUPAC representation of the elements of atomic number $ 115 $ is $ Uup $ . If true enter $ 1 $ , else enter $ 0 $ .
Answer
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Hint: Moscovium is a synthetic chemical element with the symbol $ Mc $ and atomic number $ 115 $ . In the periodic table, it is a $ p - $ block transaction element. It is a member of the $ 7th $ period and is placed in group $ 15 $ as the heaviest pnictogen, although it has not been confirmed to behave as a heavier homologue of the pnictogen bismuth.
Complete answer:
Ununpentium is a highly super heavy and an artificially produced radioactive element that has an atomic number of $ 115 $ and a symbol of $ Uup $ . The element is characterized as a metal and is known to exist as solid in nature at room temperature. It was discovered by bombarding the atoms of the element Americium $ - 243 $ with the ions of calcium.
It decays quickly within no span of time into the other elements such as the ununtrium. Ununpentium has about four isotopes with their known half-lives, of which the most stable isotope is the $ 289 $ Uup, which has a half-life measuring about $ 220 $ milliseconds. Among the products produced as a result of the bombardment were the four atoms of ununpentium and which is about less than $ \dfrac{1}{{10}} $ second got decayed into the atoms of ununtrium.
So, the correct answer is $ 1 $ .
Note:
Moscovium is predicted to be the third member of the $ 7p $ series of chemical elements and the heaviest member of group $ 15 $ in the periodic table, below bismuth. Unlike the two previous $ 7p $ elements, moscovium is expected to be a good homologue of its lighter congener, in this case bismuth. In this group, each member is known to portray the group oxidation state of $ + 5 $ but with differing stability.
Complete answer:
Ununpentium is a highly super heavy and an artificially produced radioactive element that has an atomic number of $ 115 $ and a symbol of $ Uup $ . The element is characterized as a metal and is known to exist as solid in nature at room temperature. It was discovered by bombarding the atoms of the element Americium $ - 243 $ with the ions of calcium.
It decays quickly within no span of time into the other elements such as the ununtrium. Ununpentium has about four isotopes with their known half-lives, of which the most stable isotope is the $ 289 $ Uup, which has a half-life measuring about $ 220 $ milliseconds. Among the products produced as a result of the bombardment were the four atoms of ununpentium and which is about less than $ \dfrac{1}{{10}} $ second got decayed into the atoms of ununtrium.
So, the correct answer is $ 1 $ .
Note:
Moscovium is predicted to be the third member of the $ 7p $ series of chemical elements and the heaviest member of group $ 15 $ in the periodic table, below bismuth. Unlike the two previous $ 7p $ elements, moscovium is expected to be a good homologue of its lighter congener, in this case bismuth. In this group, each member is known to portray the group oxidation state of $ + 5 $ but with differing stability.
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