It is asked, If \[\dfrac{2}{3}\] of a number is 10, then what is 1.75 of that number?
Answer
606.9k+ views
Hint: We know that \[\dfrac{2}{3}\] of a number is \[10\] so we assume the number as x then we are given that if \[\dfrac{2}{3}\] of a number is \[10\] then we write as \[\dfrac{2}{3}\times x=10\] from where we find the value of the number x which is the needed number thereafter we find the multiplication of \[1.75\] and the number which is the answer as asked in the question.
Complete step-by-step solution:
The term “\[\dfrac{2}{3}\] of a number means that if we multiply \[\dfrac{2}{3}\] with the number we get the number \[10\]”, so we write the equation
\[\dfrac{2}{3}\times x=10\]
\[\dfrac{2x}{3}=10\]
We now use cross multiplication method to separate the values to either side,
\[2x=10\times 3\]
\[x=15\]
By solving the above equation, we can obtain the value of the unknown number x, which can be done by cross multiplication method,
The line “\[1.75\] times the number” means that we have to find the number obtained by multiplying \[1.75\] and x.
For example m times the number n implies that we have to add the value of n to itself n times and so \[m\times n\]
\[1.75\times 15\]
\[26.25\]
Hence we have obtained the answer to the above question which is \[26.25\].
Note: The student must be aware of the concept of fractions as well as the concept of decimal and concept of variable. The mistakes committed by students include calculation mistakes, writing the fractions wrong, Inability to visualize the unknown number n. we must also learn how we should multiply decimal numbers which are very important.
Complete step-by-step solution:
The term “\[\dfrac{2}{3}\] of a number means that if we multiply \[\dfrac{2}{3}\] with the number we get the number \[10\]”, so we write the equation
\[\dfrac{2}{3}\times x=10\]
\[\dfrac{2x}{3}=10\]
We now use cross multiplication method to separate the values to either side,
\[2x=10\times 3\]
\[x=15\]
By solving the above equation, we can obtain the value of the unknown number x, which can be done by cross multiplication method,
The line “\[1.75\] times the number” means that we have to find the number obtained by multiplying \[1.75\] and x.
For example m times the number n implies that we have to add the value of n to itself n times and so \[m\times n\]
\[1.75\times 15\]
\[26.25\]
Hence we have obtained the answer to the above question which is \[26.25\].
Note: The student must be aware of the concept of fractions as well as the concept of decimal and concept of variable. The mistakes committed by students include calculation mistakes, writing the fractions wrong, Inability to visualize the unknown number n. we must also learn how we should multiply decimal numbers which are very important.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Find the sum of series 1 + 2 + 3 + 4 + 5 + + 100 class 9 maths CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Difference Between Plant Cell and Animal Cell

What is pollution? How many types of pollution? Define it

Which are the Top 10 Largest States of India?

Name 10 Living and Non living things class 9 biology CBSE

