
It has been found that a gaseous iodine molecule just dissociates into iodine atoms after absorption of light at wavelength $4995{{A}^{{}^\circ }}$. The energy required to dissociate 1 mole of iodine molecules is
(1) 52.2 Kcal/mole
(2) 93.4 Kcal/mole
(3) 63.4 Kcal/mole
(4) 57.3 Kcal/mole
Answer
585.3k+ views
Hint: Recollect the basic concepts of spectroscopy. We have been given a wavelength at which iodine molecules split into iodine atoms. We need to find the energy of dissociation for one mole of iodine molecules. Use the formula, $E=h\nu $ and calculate the energy for one mole of dissociation of iodine molecules.
Complete step by step solution:
- Let’s have a look at the question. It says gaseous iodine molecules dissociate into iodine atoms after absorption of electromagnetic radiation having the wavelength $4995{{A}^{{}^\circ }}$.
- We have been given a wavelength at which dissociation takes place.
- Energy is directly proportional to frequency and the formula is given as, $E=h\nu $ where h is Planck’s constant.
- For dissociation of one molecule, $E=h\nu $
- For dissociation of one mole, we will have to multiply energy by Avogadro’s number because one mole consists of Avogadro’s number of molecules.
- So now we get, $E=h\nu \times {{N}_{A}}$ …. (1)
- Now, we know that frequency is inversely proportional to wavelength and so we have the relation, $\nu =\dfrac{c}{\lambda }$ where c is the velocity of light …. (2)
- From (1) and (2) we get, $E=\dfrac{hc}{\lambda }\times {{N}_{A}}$
- Now substituting the values we get,
\[\begin{align}
& E=\dfrac{hc}{\lambda }\times {{N}_{A}} \\
& =\dfrac{6.626\times {{10}^{-34}}Js\times 3\times {{10}^{8}}m{{s}^{-1}}\times 6.023\times {{10}^{23}}mo{{l}^{-1}}}{4945\times {{10}^{-10}}m} \\
& =0.024\times {{10}^{7}}J/mol \\
& =2.4\times {{10}^{5}}J/mol \\
& E=240kJ/mol
\end{align}\]
- Now, in the options the unit used is kcal/mol so we need to convert energy in terms of kilocalories per mole.
1kJ/mol = 0.239kcal/mol
- Therefore, $E=240\times 0.239kcal/mol=57.36kcal/mol$
- Therefore, the energy required to dissociate 1 mole of iodine molecules is 57.36kcal/mol.
- Therefore, the answer is option (D).
Note: Remember energy for dissociation of one molecule is $E=h\nu $. For one mole, multiply energy with Avogadro’s number. 1kJ/mol = 0.239kcal/mol is the conversion factor for kilojoules per mole to kilocalories per mole.
Complete step by step solution:
- Let’s have a look at the question. It says gaseous iodine molecules dissociate into iodine atoms after absorption of electromagnetic radiation having the wavelength $4995{{A}^{{}^\circ }}$.
- We have been given a wavelength at which dissociation takes place.
- Energy is directly proportional to frequency and the formula is given as, $E=h\nu $ where h is Planck’s constant.
- For dissociation of one molecule, $E=h\nu $
- For dissociation of one mole, we will have to multiply energy by Avogadro’s number because one mole consists of Avogadro’s number of molecules.
- So now we get, $E=h\nu \times {{N}_{A}}$ …. (1)
- Now, we know that frequency is inversely proportional to wavelength and so we have the relation, $\nu =\dfrac{c}{\lambda }$ where c is the velocity of light …. (2)
- From (1) and (2) we get, $E=\dfrac{hc}{\lambda }\times {{N}_{A}}$
- Now substituting the values we get,
\[\begin{align}
& E=\dfrac{hc}{\lambda }\times {{N}_{A}} \\
& =\dfrac{6.626\times {{10}^{-34}}Js\times 3\times {{10}^{8}}m{{s}^{-1}}\times 6.023\times {{10}^{23}}mo{{l}^{-1}}}{4945\times {{10}^{-10}}m} \\
& =0.024\times {{10}^{7}}J/mol \\
& =2.4\times {{10}^{5}}J/mol \\
& E=240kJ/mol
\end{align}\]
- Now, in the options the unit used is kcal/mol so we need to convert energy in terms of kilocalories per mole.
1kJ/mol = 0.239kcal/mol
- Therefore, $E=240\times 0.239kcal/mol=57.36kcal/mol$
- Therefore, the energy required to dissociate 1 mole of iodine molecules is 57.36kcal/mol.
- Therefore, the answer is option (D).
Note: Remember energy for dissociation of one molecule is $E=h\nu $. For one mole, multiply energy with Avogadro’s number. 1kJ/mol = 0.239kcal/mol is the conversion factor for kilojoules per mole to kilocalories per mole.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

What organs are located on the left side of your body class 11 biology CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

How do I convert ms to kmh Give an example class 11 physics CBSE

