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Is $HBr$ stronger than ${H_2}Se$ ?

Answer
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500.4k+ views
Hint: In order to answer this question, first we will mention which given compound is stronger and then we will explain about both the compounds separately in which we will discuss the reasons behind it. And atlast we will discuss the health effect of ${H_2}Se$ .

Complete answer:
Yes, hydrogen bromide ($HBr$ ) is stronger than hydrogen selenide (${H_2}Se$ ).
The inorganic compound $HBr$ stands for hydrogen bromide. It's a hydrogen halide made up of two elements: hydrogen and bromine. It is a colourless gas that dissolves in water to generate hydrobromic acid, which is saturated at room temperature with $68.85\% $ $HBr$ by weight. A constant-boiling azeotrope mixture is formed by aqueous solutions containing $47.6\% $ $HBr$ by mass, which boils at \[{124.3^\circ }C\] . Boiling less concentrated solutions releases H2O until the mixture composition reaches the constant-boiling point. In the synthesis of bromide compounds, hydrogen bromide and its aqueous solution are extensively employed reagents.
The inorganic compound hydrogen selenide (${H_2}Se$ ) has the formula ${H_2}Se$ . This hydrogen chalcogenide is the most basic and regularly encountered selenium hydride. Under normal circumstances, ${H_2}Se$ is a colourless, combustible gas. With an exposure limit of $0.05ppm$ over an \[8hr\] period, it is the most lethal selenium compound. This chemical has a highly unpleasant odour that smells like rotting horseradish or 'leaking gas' even at very low concentrations, but smells like rotten eggs at greater ones.
Hence, $HBr$ is a strong acid whereas ${H_2}Se$ is a weak acid.

Note:
The colourless gas hydrogen selenide has an unpleasant odour. It's extremely flammable and poisonous. It has the potential to irritate the eyes and mucous membranes. It has a higher density than air. Inhalation can have adverse health effects after long-term exposure to low doses or short-term exposure to high amounts.