Question

Is a temperature of $55$$^ \circ F$ approximately equivalent to $13$$^ \circ C$?

Answer 1

Hint: Temperature is defined as the physical quantity of any matter which usually expresses the hold and cold condition of matter. Temperature is a property of thermal energy which changes the temperature of any body.

Complete answer:
Temperature changes with the flow of heat from the hotter body to the colder body. Temperature always flows from the higher temperature to lower temperature.
Temperature changes when two bodies come into physical contact by conduction or by convection or by radiation. There are number of standard units which are used to express the temperature such as Celsius $\left( {^ \circ C} \right)$, Fahrenheit $\left( {^ \circ F} \right)$ and Kelvin $\left( K \right)$.
We can convert Celsius to kelvin by using formula: $^ \circ C = K - 273.15$
Similarly, we can convert kelvin into Celsius by using formula: $K{ = ^ \circ }C + 273.15$
All these units are related with each other by a mathematical expression:
$F = \dfrac{9}{5}C + 32$
We can modify this mathematical expression in terms of Celsius
$^ \circ C = \left( {^ \circ F - 32} \right) \times \dfrac{5}{9}$
Value of temperature in Fahrenheit is given $55$$^ \circ F$, so value of temperature in Celsius is:
$^ \circ C = \left( {55 - 32} \right) \times \dfrac{5}{9}$
On solving the above equation, we get
$^ \circ C = \left( {23} \right) \times \dfrac{5}{9}$
On simplifying the above equation, we get
$^ \circ C = 12.77$
On rounding off the above value upto two digits we get
$^ \circ C = 13$
$ \Rightarrow $ Therefore, temperature of $55$$^ \circ F$ approximately equivalent to $13$$^ \circ C$.

Note:
Absolute zero is a temperature which is considered as the lowest theoretical temperature possible for any substance. We can convert Fahrenheit into kelvin by using formula $^ \circ F = K - 457.87$. Do not get confused with the term temperature coefficient which is a relative change in physical characteristics of any material associated with temperature change.