
Is \[{\text{2Na + 2}}{{\text{H}}_{\text{2}}}{\text{O}} \to {\text{2NaOH + }}{{\text{H}}_{\text{2}}}\] a redox reaction?
Answer
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Hint: We have to know that in chemistry, equations play a major role. In the reaction three things are main. There are reactants, products and reaction conditions. The reactants are always on the left side of the equation. If more than one reactant in the equation means by using plus sign. The products are always on the right side of the reaction. Something here also follows. More than one product by using plus sign. In between reactant products are used arrows to find the reaction direction in the equation. In chemistry two main reactions play a major role. One is the oxidation reaction. Another is the reduction reaction. Oxidation reaction is nothing but addition of oxidation or removal of hydrogen or loss of electrons. Reduction is nothing but addition of hydrogen or removal of oxygen or gain of electrons in the reaction form reactant to product.
Complete answer:
The given chemical reaction is
\[{\text{2Na + 2}}{{\text{H}}_{\text{2}}}{\text{O}} \to {\text{2NaOH + }}{{\text{H}}_{\text{2}}}\]
Sodium reacts with water to form sodium hydroxide as an oxidation reaction. Because the oxidation state of sodium was changed from zero to one. Water is changed to hydrogen gas in a reduction reaction.
This kind of oxidation reaction and reduction reaction happens one reaction means that evasion is called redox reaction.
According to the above discussion, we conclude \[{\text{2Na + 2}}{{\text{H}}_{\text{2}}}{\text{O}} \to {\text{2NaOH + }}{{\text{H}}_{\text{2}}}\] is a one of the redox reaction.
Note:
As we know that in balanced chemical reaction wise, we predict the side product of the reaction. In some cases we are not able to attain balance by changing the mole. In that case we use the number of countable ions in the product and reactant side of the chemical reaction. In chemistry, redox reaction is one of the types of major reactions. In this redox reaction two methods are used to attain the balanced chemical reaction. There are ion-electron methods and the oxidation number method.
Complete answer:
The given chemical reaction is
\[{\text{2Na + 2}}{{\text{H}}_{\text{2}}}{\text{O}} \to {\text{2NaOH + }}{{\text{H}}_{\text{2}}}\]
Sodium reacts with water to form sodium hydroxide as an oxidation reaction. Because the oxidation state of sodium was changed from zero to one. Water is changed to hydrogen gas in a reduction reaction.
This kind of oxidation reaction and reduction reaction happens one reaction means that evasion is called redox reaction.
According to the above discussion, we conclude \[{\text{2Na + 2}}{{\text{H}}_{\text{2}}}{\text{O}} \to {\text{2NaOH + }}{{\text{H}}_{\text{2}}}\] is a one of the redox reaction.
Note:
As we know that in balanced chemical reaction wise, we predict the side product of the reaction. In some cases we are not able to attain balance by changing the mole. In that case we use the number of countable ions in the product and reactant side of the chemical reaction. In chemistry, redox reaction is one of the types of major reactions. In this redox reaction two methods are used to attain the balanced chemical reaction. There are ion-electron methods and the oxidation number method.
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