
Is $ 25 $ a multiple of $ 2 $ or $ 5 $ ? How do you know?
Answer
543.6k+ views
Hint: In order to determine whether $ 25 $ a multiple of $ 2 $ or $ 5 $ , we can use many methods. First we will determine the condition by listing out the multiples of $ 2 $ or $ 5 $ . Then, we know that multiples of $ 2 $ only contain even numbers and multiples of $ 5 $ only contain numbers that end with $ 0 $ or $ 5 $ . Thus, by using this logic we will determine the given. Then, we will also determine the given using the prime factorization method, as both $ 2 $ and $ 5 $ are prime numbers.
Complete step-by-step answer:
Now, we need to determine whether $ 25 $ a multiple of $ 2 $ or $ 5 $ .
Now, let us list out the multiples of $ 2 $ ,
$ 2,4,6,8,10,12,14,16,18,20,22,24,26 $
It is clear that the multiples of $ 2 $ skip the number $ 25 $ . Therefore, we can say that $ 25 $ is not a multiple of $ 2 $ .
Here, let us list out the multiples of $ 5 $ ,
$ 5,10,15,20,25 $
It is clear that $ 25 $ is a multiple of $ 5 $ .
Alternative:
Also, we know that is $ 25 $ an odd number. And multiplies of $ 2 $ only contain even numbers. Hence, we can say that $ 25 $ is not a multiple of $ 2 $ .
On the other hand, we know that multiples of $ 5 $ only contain numbers that end with $ 0 $ or $ 5 $ . Thus, we can conclude that $ 25 $ is a multiple of $ 5 $ .
Alternative:
We can also use prime factorization to know $ 25 $ a multiple of $ 2 $ or $ 5 $ , as both $ 2 $ and $ 5 $ are prime numbers.
Therefore, the prime factorization of $ 25 $ is,
$ 25 = 5 \times 5 $
Hence, it is clear that $ 25 $ is not a multiple of $ 2 $ and it is a multiple of $ 5 $ .
So, the correct answer is “5”.
Note: Prime factorization of a number is breaking down a number into the set of prime numbers which multiply together to result in the original number. This is also known as prime decomposition or integer factorization.
Complete step-by-step answer:
Now, we need to determine whether $ 25 $ a multiple of $ 2 $ or $ 5 $ .
Now, let us list out the multiples of $ 2 $ ,
$ 2,4,6,8,10,12,14,16,18,20,22,24,26 $
It is clear that the multiples of $ 2 $ skip the number $ 25 $ . Therefore, we can say that $ 25 $ is not a multiple of $ 2 $ .
Here, let us list out the multiples of $ 5 $ ,
$ 5,10,15,20,25 $
It is clear that $ 25 $ is a multiple of $ 5 $ .
Alternative:
Also, we know that is $ 25 $ an odd number. And multiplies of $ 2 $ only contain even numbers. Hence, we can say that $ 25 $ is not a multiple of $ 2 $ .
On the other hand, we know that multiples of $ 5 $ only contain numbers that end with $ 0 $ or $ 5 $ . Thus, we can conclude that $ 25 $ is a multiple of $ 5 $ .
Alternative:
We can also use prime factorization to know $ 25 $ a multiple of $ 2 $ or $ 5 $ , as both $ 2 $ and $ 5 $ are prime numbers.
Therefore, the prime factorization of $ 25 $ is,
$ 25 = 5 \times 5 $
Hence, it is clear that $ 25 $ is not a multiple of $ 2 $ and it is a multiple of $ 5 $ .
So, the correct answer is “5”.
Note: Prime factorization of a number is breaking down a number into the set of prime numbers which multiply together to result in the original number. This is also known as prime decomposition or integer factorization.
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