Question

What is the ionic compound for $C{{a}_{3}}{{(P{{O}_{4}})}_{2}}$ ?

Answer 1

Hint: Ionic compounds are the compounds formed by gaining and losing electrons to form a net positive, negative or neutral charge. One atom lose electrons while the other gains in order to form a bond.

Complete step by step answer:
Ionic compounds are formed by positively charged cations and negatively charged anions to form neutral compounds (most commonly).
Usually metals lose electrons and hence have a net positive charge to become cations while on the other hand non-metals gain electrons to have a net negative charge forming anions.
Ionic compounds have high melting and boiling point and are strong and brittle.
To write an ionic compound we first need to know the cation, it’s symbol and charge and anion, it’s symbol and charge. In ionic compounds, the cation that is the positive charge is written first followed by anion that is the negative charge to form the neutral compounds.
Ionic compounds do not exist as molecules; they are crystals in solid state like sodium sulfide.
Our given compound $C{{a}_{3}}{{(P{{O}_{4}})}_{2}}$ is Calcium Phosphate made from cation calcium and anion phosphate. The cation calcium is $C{{a}^{2+}}$ and anion is phosphate $PO_{4}^{3-}$. This formula indicates that it has three calcium ions for every two phosphate groups.

Note: We obtain formula from the name by cross multiplying their valencies and vice versa we can obtain the name and ions used by breaking the bond.
The given compound is neutral ionic compounds because both fullfills each other’s requirements by giving and taking.