Question

What is the ionic bond formation of \[NaCl\]?
A) \[Na\; \to \;\;N{a^ + } + {\text{ }}{e^ - }\] and \[Cl{\text{ }} + {\text{ }}{e^ - } \to \;\;C{l^ - }\]
B) \[Na\; \to \;\;N{a^ + } + {\text{ }}{e^ - }\] and \[Cl{\text{ }} \to \;\;C{l^ - } + {e^ - }\]
C) Bond formed between \[N{a^ + }\] and \[C{l^ - }\] ions
D) Both A and C

Answer 1

Hint: The sodium chloride is a neutral compound as it has no charge, the ions due to which \[NaCl\] is formed is \[N{a^ + }\] and \[C{l^ - }\].

Complete step by step answer:
We have to remember that the \[NaCl\] is an ionic compound which is commonly called as rock salt and has a chemical name as Sodium chloride.
It is formed by addition of two ions which are \[N{a^ + }\] and \[C{l^ - }\] .These two ions are present in equal ratio in this moiety.
The reaction for the formation of sodium chloride is as follows:
\[N{a^ + } + C{l^ - } \to NaCl\]
Electronic configuration of\[Na\]: \[1{s^2}2{s^2}2{p^6}3{s^1}\]
Electronic configuration of\[Cl\]: \[1{s^2}2{s^2}2{p^6}3{s^2}3{p^5}\]
\[Na\] has one electron in excess to attain stable electronic configuration whereas \[Cl\] is deficient of one electron to get its octet filled.
So this is how an ionic bond is formed in sodium chloride, when an electron from \[Na\] is transferred to \[Cl\]making both the atoms attaining stable octet configuration will lead to ionic bond formation.
Electronic configuration of\[N{a^ + }\]:\[1{s^2}2{s^2}2{p^6}\]
Electronic configuration of\[C{l^ - }\]: \[1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}\]
So by looking at this electronic configuration we can predict that \[Na\] lose an electron to attain electronic configuration whereas \[Cl\]gains an electron and this is how an ionic bond is formed between \[N{a^ + }\] and \[C{l^ - }\].
Option A) This option can be correct \[Na\]lose an electron to form \[N{a^ + }\] whereas \[Cl\]gain an electron to form \[C{l^ - }\] and that how an ionic bond is formed i.e. \[N{a^ + } + C{l^ - } \to NaCl\].
Option B) This is an incorrect option as when \[Cl\]will lose an electron it will not attain stable electronic configuration therefore no bond is as there is no electron transfer between \[Na\] and \[Cl\].
Option C) This option can be correct as an ionic bond is formed between \[N{a^ + }\] and \[C{l^ - }\].
Option D) This is a correct option as it has both the options which are correct i.e. option A and C.

Hence, the correct answer is, ‘Option D’.

Note: \[NaCl\]is an ionic bond that is formed with the exchange of ions between sodium and chloride ions. We also remember that the sodium chloride is a white crystalline solid having melting point of $801^\circ C$ and also know that the sodium chloride is readily soluble in water and other polar solvents.