Integrate the function \[\sqrt {4 - {x^2}} \]
Answer
623.1k+ views
Hint: The simple meaning of trigonometry is calculations of triangles. For solving this question, we will use some identities, As there is a square root present in the question. We have some formulas/ identities, so using that question will be very easy to solve.
(A) \[\int {\sqrt {{a^2} - {x^2}} } dx = \dfrac{x}{2}\sqrt {{a^2} - {x^2}} + \dfrac{{{a^2}}}{2}{\sin ^{ - 1}}\dfrac{x}{a} + c\]
By taking the above identity, we can solve the given question.
Complete step-by-step answer:
We also have some identities
(A) \[\int {\sqrt {{a^2} - {x^2}} } dx = \dfrac{x}{2}\sqrt {{a^2} - {x^2}} + \dfrac{{{a^2}}}{2}{\sin ^{ - 1}}\dfrac{x}{a} + c\]
(B) \[\int {\sqrt {{a^2} + {x^2}} } dx = \dfrac{x}{2}\sqrt {{a^2} + {x^2}} + \dfrac{{{a^2}}}{2}\log \left| {x + \sqrt {{x^2} + {a^2}} } \right| + c\]
(C) \[\int {\sqrt {{x^2} - {a^2}} } dx = \dfrac{x}{2}\sqrt {{x^2} - {a^2}} - \dfrac{{{a^2}}}{2}\log \left| {x + \sqrt {{x^2} - {a^2}} } \right| + c\]
For solving this question, we will use the identity (A),
According to that the value of a is 2 and x is x, so-
\[\int {\sqrt {{a^2} - {x^2}} } dx = \dfrac{x}{2}\sqrt {{a^2} - {x^2}} + \dfrac{{{a^2}}}{2}{\sin ^{ - 1}}\dfrac{x}{a} + c\]
Now, use this identity,
In question, Given that, \[\int {\sqrt {4 - {x^2}} } \] , for integrating the given function, we can use the identity.
Here, \[4 = {(2)^2}\] .
So = \[\int {\sqrt {{{\left( 2 \right)}^2} - {x^2}} } dx\] (Start substituting in the given identity)
We get,= \[\dfrac{x}{2}\sqrt {4 - {x^2}} + \dfrac{4}{2}{\sin ^{ - 1}}\dfrac{x}{2} + c\]
= \[\dfrac{{x\sqrt {4 - {x^2}} }}{2} + \dfrac{4}{2}{\sin ^{ - 1}}\left( {\dfrac{x}{2}} \right) + c\]
\[\int {\sqrt {4 - {x^2}} } \] = \[\dfrac{{x\sqrt {4 - {x^2}} }}{2} + \dfrac{4}{2}{\sin ^{ - 1}}\left( {\dfrac{x}{2}} \right) + c\]
So, this will be the answer.
So, the correct answer is “ \[\dfrac{{x\sqrt {4 - {x^2}} }}{2} + \dfrac{4}{2}{\sin ^{ - 1}}\left( {\dfrac{x}{2}} \right) + c\] ”.
Note: In this question, we are using identities, by using that question will be easy to solve. By choosing the correct identity for solving the question remember to check the a and x value. Also remember to check the positive and negative signs. The simple meaning of trigonometry is calculations of triangles. Also, in physics, trigonometry is used to find the components of vectors and also in projectile motion have a lot of application of trigonometry.
(A) \[\int {\sqrt {{a^2} - {x^2}} } dx = \dfrac{x}{2}\sqrt {{a^2} - {x^2}} + \dfrac{{{a^2}}}{2}{\sin ^{ - 1}}\dfrac{x}{a} + c\]
By taking the above identity, we can solve the given question.
Complete step-by-step answer:
We also have some identities
(A) \[\int {\sqrt {{a^2} - {x^2}} } dx = \dfrac{x}{2}\sqrt {{a^2} - {x^2}} + \dfrac{{{a^2}}}{2}{\sin ^{ - 1}}\dfrac{x}{a} + c\]
(B) \[\int {\sqrt {{a^2} + {x^2}} } dx = \dfrac{x}{2}\sqrt {{a^2} + {x^2}} + \dfrac{{{a^2}}}{2}\log \left| {x + \sqrt {{x^2} + {a^2}} } \right| + c\]
(C) \[\int {\sqrt {{x^2} - {a^2}} } dx = \dfrac{x}{2}\sqrt {{x^2} - {a^2}} - \dfrac{{{a^2}}}{2}\log \left| {x + \sqrt {{x^2} - {a^2}} } \right| + c\]
For solving this question, we will use the identity (A),
According to that the value of a is 2 and x is x, so-
\[\int {\sqrt {{a^2} - {x^2}} } dx = \dfrac{x}{2}\sqrt {{a^2} - {x^2}} + \dfrac{{{a^2}}}{2}{\sin ^{ - 1}}\dfrac{x}{a} + c\]
Now, use this identity,
In question, Given that, \[\int {\sqrt {4 - {x^2}} } \] , for integrating the given function, we can use the identity.
Here, \[4 = {(2)^2}\] .
So = \[\int {\sqrt {{{\left( 2 \right)}^2} - {x^2}} } dx\] (Start substituting in the given identity)
We get,= \[\dfrac{x}{2}\sqrt {4 - {x^2}} + \dfrac{4}{2}{\sin ^{ - 1}}\dfrac{x}{2} + c\]
= \[\dfrac{{x\sqrt {4 - {x^2}} }}{2} + \dfrac{4}{2}{\sin ^{ - 1}}\left( {\dfrac{x}{2}} \right) + c\]
\[\int {\sqrt {4 - {x^2}} } \] = \[\dfrac{{x\sqrt {4 - {x^2}} }}{2} + \dfrac{4}{2}{\sin ^{ - 1}}\left( {\dfrac{x}{2}} \right) + c\]
So, this will be the answer.
So, the correct answer is “ \[\dfrac{{x\sqrt {4 - {x^2}} }}{2} + \dfrac{4}{2}{\sin ^{ - 1}}\left( {\dfrac{x}{2}} \right) + c\] ”.
Note: In this question, we are using identities, by using that question will be easy to solve. By choosing the correct identity for solving the question remember to check the a and x value. Also remember to check the positive and negative signs. The simple meaning of trigonometry is calculations of triangles. Also, in physics, trigonometry is used to find the components of vectors and also in projectile motion have a lot of application of trigonometry.
Recently Updated Pages
Onehalf of a convex lens is covered with a black paper class 12 physics CBSE

Differentiate between lanthanoids and actinoids class 12 chemistry CBSE

An object 5 cm in length is held 25 cm away from a class 12 physics CBSE

Name the following halides according to the IUPAC system class 12 chemistry CBSE

An infinite ladder network of resistances is constructed class 12 physics CBSE

How will you bring about the following conversions class 12 chemistry CBSE

Trending doubts
Draw a labelled sketch of the human eye class 12 physics CBSE

Which are the Top 10 Largest Countries of the World?

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?

