
$\int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (4 + x)}}{{\ln (4 + x) + \ln (9 - x)}}dx} $ is equal to:
1. Cannot be evaluated
2. Is equal to $\dfrac{5}{2}$
3. Is equal to $1 + 2\ln 3$
4. Is equal to $\dfrac{1}{2} + \ln 3$
Answer
554.4k+ views
Hint: We have to integrate the given complex function. It is a definite function so we will get a constant answer and we will not add any constant of integration at the end. We will use formulas of integration to solve it. It is going to be very difficult to solve it directly so we will use a different formula to solve this equation.
Complete step by step solution:
According to the question we have to integrate $\int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (4 + x)}}{{\ln (4 + x) + \ln (9 - x)}}dx} $
So, we will use the integration formula $\int_x^a {f(x) = } \int_b^a {f(a + b - x)} $, this is also called as King’s rule.
This formula represents that we can add both the limits with the variable of the function in the integration and yet, the value will not change. It helps to simplify the equation and solve the equation easily.
So, now let us say $I = \int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (4 + x)}}{{\ln (4 + x) + \ln (9 - x)}}dx} $ (Consider it as equation 1)
Now, we will use king’s rule in $I$
So we will get
$ \Rightarrow I = \int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (4 + 3 + \ln 3 + 2 - \ln 3 - x)}}{{\ln (4 + 3 + \ln 3 + 2 - \ln 3 - x) + \ln (9 - 3 - \ln 3 - 2 + \ln 3 + x)}}dx} $
It can be solved as
$ \Rightarrow I = \int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (9 - x)}}{{\ln (9 - x) + \ln (4 + x)}}dx} $ (Consider it as equation 2)
Now, we will add equation one and equation two, so we will get
$ \Rightarrow 2I = \int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (9 - x) + \ln (4 + x)}}{{\ln (9 - x) + \ln (4 + x)}}dx} $
$ \Rightarrow 2I = \int_{2 - \ln 3}^{3 + \ln 3} {1dx} $ (As numerator and denominator are equal)
$ \Rightarrow 2I = 3 + \ln 3 - 2 + \ln 3$ (Integration of one is x)
$ \Rightarrow I = \dfrac{1}{2}(1 + 2\ln 3)$
$ \Rightarrow I = \dfrac{1}{2} + \ln 3$
Hence, option four is our answer.
Note:
We have used king’s rule to solve it because we can’t solve the equation directly easily. It helps to simplify the equation and solve the equation easily. We basically add the new equation we get after using king’s rule and the previous equation to solve the questions in which we use king’s rule. We need to know the integration rule to solve these types of questions.
Complete step by step solution:
According to the question we have to integrate $\int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (4 + x)}}{{\ln (4 + x) + \ln (9 - x)}}dx} $
So, we will use the integration formula $\int_x^a {f(x) = } \int_b^a {f(a + b - x)} $, this is also called as King’s rule.
This formula represents that we can add both the limits with the variable of the function in the integration and yet, the value will not change. It helps to simplify the equation and solve the equation easily.
So, now let us say $I = \int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (4 + x)}}{{\ln (4 + x) + \ln (9 - x)}}dx} $ (Consider it as equation 1)
Now, we will use king’s rule in $I$
So we will get
$ \Rightarrow I = \int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (4 + 3 + \ln 3 + 2 - \ln 3 - x)}}{{\ln (4 + 3 + \ln 3 + 2 - \ln 3 - x) + \ln (9 - 3 - \ln 3 - 2 + \ln 3 + x)}}dx} $
It can be solved as
$ \Rightarrow I = \int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (9 - x)}}{{\ln (9 - x) + \ln (4 + x)}}dx} $ (Consider it as equation 2)
Now, we will add equation one and equation two, so we will get
$ \Rightarrow 2I = \int_{2 - \ln 3}^{3 + \ln 3} {\dfrac{{\ln (9 - x) + \ln (4 + x)}}{{\ln (9 - x) + \ln (4 + x)}}dx} $
$ \Rightarrow 2I = \int_{2 - \ln 3}^{3 + \ln 3} {1dx} $ (As numerator and denominator are equal)
$ \Rightarrow 2I = 3 + \ln 3 - 2 + \ln 3$ (Integration of one is x)
$ \Rightarrow I = \dfrac{1}{2}(1 + 2\ln 3)$
$ \Rightarrow I = \dfrac{1}{2} + \ln 3$
Hence, option four is our answer.
Note:
We have used king’s rule to solve it because we can’t solve the equation directly easily. It helps to simplify the equation and solve the equation easily. We basically add the new equation we get after using king’s rule and the previous equation to solve the questions in which we use king’s rule. We need to know the integration rule to solve these types of questions.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

RNA and DNA are chiral molecules their chirality is class 12 chemistry CBSE

RNA and DNA are chiral molecules their chirality is class 12 chemistry CBSE

