
In what range do you expect the density of the sun to be, in the range of densities of solids and liquids or gases? Briefly explain with the help of the following data:
Mass of the sun= $ 2.0\times {{10}^{30}}kg $ and radius of the sun= $ 7.0\times {{10}^{8}}m $
Answer
579.3k+ views
Hint: First try to look out for the data that is given in the question, we know that the sun is actually a large sphere. So we need to calculate the volume of the sphere, by the general formula for volume. Now we have got the mass and the volume of the sphere that calculate the density and compare it with the density of solid, liquid and gas.
Formula used:
$ V=\dfrac{4}{3}\pi {{r}^{3}} $ Density= Mass/volume
Complete step-by-step answer:
Mass of the sun is = $ 2.0\times {{10}^{30}}kg $ (given)
Radius of the sun is = $ 7.0\times {{10}^{8}}m $ (given)
Now, to know the volume of the sun, we know that sun is a huge sphere
So,
$ V=\dfrac{4}{3}\pi {{r}^{3}} $,
$ V=\dfrac{4}{3}\times \dfrac{22}{7}\times {{\left( 7.0\times {{10}^{8}} \right)}^{3}} $ ,
Therefore on solving we get the volume as,
$ V=1437.3\times {{10}^{24}}{{m}^{3}} $.
We know that formula for density is,
Density= Mass/volume.
So,
$ D=\dfrac{2.0\times {{10}^{30}}}{1437.3\times {{10}^{24}}} $ ,
Which on solving is equivalent to,
$ D=1.4\times {{10}^{3}}kg/{{m}^{3}} $ .
Therefore on seeing the density of the sun we can say that it has a density range similar to solids and liquids, and this high density is achieved due to the intense gravitational pull of the inner layers on the outer layers of the sun.
Additional Information: Density is actually the calculation or magnitude of the amount of matter in a given space.
The amount of matter is referred to in the SI system as mass of the body.
Note: The high density of the sun is in the similar range of the solids and liquids only but not of gases. When solving the questions try to calculate the powers of 10 carefully as a small mistake can make the whole answer wrong.
Formula used:
$ V=\dfrac{4}{3}\pi {{r}^{3}} $ Density= Mass/volume
Complete step-by-step answer:
Mass of the sun is = $ 2.0\times {{10}^{30}}kg $ (given)
Radius of the sun is = $ 7.0\times {{10}^{8}}m $ (given)
Now, to know the volume of the sun, we know that sun is a huge sphere
So,
$ V=\dfrac{4}{3}\pi {{r}^{3}} $,
$ V=\dfrac{4}{3}\times \dfrac{22}{7}\times {{\left( 7.0\times {{10}^{8}} \right)}^{3}} $ ,
Therefore on solving we get the volume as,
$ V=1437.3\times {{10}^{24}}{{m}^{3}} $.
We know that formula for density is,
Density= Mass/volume.
So,
$ D=\dfrac{2.0\times {{10}^{30}}}{1437.3\times {{10}^{24}}} $ ,
Which on solving is equivalent to,
$ D=1.4\times {{10}^{3}}kg/{{m}^{3}} $ .
Therefore on seeing the density of the sun we can say that it has a density range similar to solids and liquids, and this high density is achieved due to the intense gravitational pull of the inner layers on the outer layers of the sun.
Additional Information: Density is actually the calculation or magnitude of the amount of matter in a given space.
The amount of matter is referred to in the SI system as mass of the body.
Note: The high density of the sun is in the similar range of the solids and liquids only but not of gases. When solving the questions try to calculate the powers of 10 carefully as a small mistake can make the whole answer wrong.
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