Question

In water, the reaction of $NaOH$ and ${H_2}S{O_2}$ goes to completion because:
A.It is a neutralization reaction
B.Water is a strong electrolyte
C.Sodium sulfate quickly precipitates
D.A volatile product is formed
E.Sulfuric acid is very strong acid

Answer 1

Hint: We can define double displacement reactions as reactions that occur when the cation and the anions switch between two reactants to form new products. In order for the neutralization reaction to take place, one of the products formed would be a solid precipitate, a gas or a molecular compound.
Example: The product of the reaction between nitric acid and calcium sulphide is gaseous hydrogen sulphide and calcium nitrate. The completed equation is,
$CaS\left( s \right) + 2HN{O_3}\left( {aq} \right)\xrightarrow{{}}Ca{\left( {N{O_3}} \right)_2}\left( {aq} \right) + {H_2}S\left( g \right)$

Complete step by step answer:
We must remember that the sulfoxylic acid (or) hyposulfurous acid has a chemical formula of ${H_2}S{O_2}$ and sodium hydroxide has a chemical formula of $NaOH$. When hyposulfurous acid and sodium hydroxide reacts in water, they form the products Sodium Hyposulfite and water. The formula of Sodium Hyposulfite is $N{a_2}S{O_2}$.
We can write the chemical reaction as,
\[{H_2}S{O_2}\left( {aq} \right) + 2NaOH\left( {aq} \right) \to N{a_2}S{O_2}\left( {aq} \right) + 2{H_2}O\left( l \right)\]
Here, hyposulfurous acid acts as an acid and sodium hydroxide acts as a base.
We can say a chemical reaction between an acid and a base is called a neutralization reaction. The ionic compound formed along with water in this reaction is called salt.
Therefore, the option (A) is correct.
Water is a weak electrolyte and not a strong electrolyte.
Therefore, the option (B) is incorrect.
Sodium sulfate is water-soluble and no precipitation happens.
Therefore, the option (C) is incorrect.
The products formed are Sodium Hyposulfite and water. Both these products are non-volatile.
Therefore, the option (D) is incorrect.
The given acid is sulfoxylic acid not sulfuric acid.
Therefore, the option (E) is incorrect.

So, the correct answer is Option A.

Note:
We also remember that the reaction of acetic acid and calcium carbonate is an acid-base or neutralization reaction. The product formed by the neutralization reaction of acetic acid and calcium carbonate is calcium acetate and carbonic acid. The neutralization reaction is,
$2C{H_3}COO{H_{\left( {aq} \right)}} + CaC{O_{3(aq)}}\xrightarrow{{}}{H_2}C{O_{3(aq)}} + Ca{\left( {C{H_3}COO} \right)_{2(aq)}}$
${\text{Acetic acid Calcium carbonate Carbonic Acid Calciumacetate}}$
Here, acetic acid is the acid and calcium carbonate is the base.
Carbonic acid decomposes into water and carbon dioxide due to its unstable nature. Hence, the neutralization reaction is,
$2C{H_3}COO{H_{\left( {aq} \right)}} + CaC{O_{3(aq)}}\xrightarrow{{}}{H_2}{O_{\left( l \right)}} + C{O_{2(g)}} + Ca{\left( {C{H_3}COO} \right)_{2(aq)}}$
${\text{Acetic acid Calcium carbonate Water Carbon Dioxide Calcium Acetate}}$