
In two step pulley arrangement meant for a load \[W\], the ratio between force \[P\] and \[W\] equilibrium position, when radii of pulleys are \[{r_1}\] and \[{r_2}\] :
\[\left( {\text{A}} \right){\text{ }}\dfrac{{{r_{\text{2}}}}}{{{r_r}{\text{ - }}{r_{\text{2}}}}}\]
\[\left( {\text{B}} \right){\text{ }}\dfrac{{{r_1} - {r_2}}}{{{r_2}}}\]
\[\left( {\text{C}} \right){\text{ }}\dfrac{{{r_1}}}{{{r_2} - {r_1}}}\]
\[\left( {\text{D}} \right){\text{ }}\dfrac{{{r_2} - {r_1}}}{{{r_1}}}\]
Answer
573k+ views
Hint:The two pulley arrangement is given force \[P\] and also the work is done at the centre of the pulley. The pulley remains constant means it doesn’t change its position due to the force and the load. Therefore the effect of load and the force is equal and opposite.
Complete step by answer:
From the question, the ratio of a small circle in the pulley is \[{r_2}\]. And the load \[W\] concentrates at the centre of both the pulleys which is \[{r_2}\]. Due to the effect of the load \[W\], the pulley rotates at a small angle called \[{r_2}\theta \]
The force \[P\] is given to the circle of radius \[{r_1} - {r_2}\]. Due to the force \[P\] the pulley experiences the rotation equals to \[({r_1} - {r_2})\theta \]
The condition given is that the pulley remains in the equilibrium position. Hence the resultant action by the force \[P\] and the load \[W\]is equal and opposite. Therefore,
\[P\left[ {({r_1} - {r_2})\theta } \right] - W({r_2}\theta ) = 0\]
We have to write the terms as equate form
\[ \rightarrow P\left[ {({r_1} - {r_2})\theta } \right] = W({r_2}\theta )\]
Also, write it as the fraction term so we divided the terms we get,
\[ \rightarrow \dfrac{P}{W} = \dfrac{{{r_2}\theta }}{{({r_1} - {r_2})\theta }}\]
Cancel the same term we get,
\[\therefore \dfrac{P}{W} = \dfrac{{{r_2}}}{{({r_1} - {r_2})}}\]
Hence, the ratio between the force \[P\] and the load \[W\] in equilibrium is \[\dfrac{{{r_2}}}{{{r_1} - {r_2}}}\].
Therefore the correct option is A.
Note:Pulleys are used for the mechanism to lift the weight. It reduces the force required for lifting the weight. In two pulley arrangements, one pulley is fixed at its centre point and another pulley is movable. As the weight is loaded on the pulley, the pulley should be two times heavier than the load. Pulleys have many applications in our day to day life. It is used in wells to carry water from the well using the bucket; elevators have multiple pulleys, etc.
Complete step by answer:
From the question, the ratio of a small circle in the pulley is \[{r_2}\]. And the load \[W\] concentrates at the centre of both the pulleys which is \[{r_2}\]. Due to the effect of the load \[W\], the pulley rotates at a small angle called \[{r_2}\theta \]
The force \[P\] is given to the circle of radius \[{r_1} - {r_2}\]. Due to the force \[P\] the pulley experiences the rotation equals to \[({r_1} - {r_2})\theta \]
The condition given is that the pulley remains in the equilibrium position. Hence the resultant action by the force \[P\] and the load \[W\]is equal and opposite. Therefore,
\[P\left[ {({r_1} - {r_2})\theta } \right] - W({r_2}\theta ) = 0\]
We have to write the terms as equate form
\[ \rightarrow P\left[ {({r_1} - {r_2})\theta } \right] = W({r_2}\theta )\]
Also, write it as the fraction term so we divided the terms we get,
\[ \rightarrow \dfrac{P}{W} = \dfrac{{{r_2}\theta }}{{({r_1} - {r_2})\theta }}\]
Cancel the same term we get,
\[\therefore \dfrac{P}{W} = \dfrac{{{r_2}}}{{({r_1} - {r_2})}}\]
Hence, the ratio between the force \[P\] and the load \[W\] in equilibrium is \[\dfrac{{{r_2}}}{{{r_1} - {r_2}}}\].
Therefore the correct option is A.
Note:Pulleys are used for the mechanism to lift the weight. It reduces the force required for lifting the weight. In two pulley arrangements, one pulley is fixed at its centre point and another pulley is movable. As the weight is loaded on the pulley, the pulley should be two times heavier than the load. Pulleys have many applications in our day to day life. It is used in wells to carry water from the well using the bucket; elevators have multiple pulleys, etc.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Why is steel more elastic than rubber class 11 physics CBSE

What is boron A Nonmetal B Metal C Metalloid D All class 11 chemistry CBSE

What is Environment class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

How many squares are there in a chess board A 1296 class 11 maths CBSE

