
In traffic signals, color light is used to stop vehicles because its wavelength is ?
Answer
475.5k+ views
Hint: To solve the question we should know about the scattering of light and how it is related to wavelength. And we should also know about the relation between wavelength and frequency. The scattering of the light is inversely proportional to the fourth power of the light of concern.
Complete step by step solution:
To solve the question we should know which color is used for the signal to stop the vehicles. And we should also know the relation between the wavelength, frequency, and scattering of light.
The phenomenon of scattering refers to when a light ray is passed through a medium then some of the rays get absorbed by the medium and the majority of the ray gets deflected from its path and ie the rays get scattered. And this phenomenon observed is called scattering.
Now we should know what wavelength of the light refers to. The wavelength of the light can be defined as the distance between the two troughs or two crests. We should know which light has the highest wavelength and lowest wavelength. The highest wavelength is observed by red light among the visible light and the least wavelength is observed by the blue light among the visible light
Now we should establish a relation between the wavelength of the light and the scattering phenomenon.
The scattering of light is inversely proportional to the fourth power of the wavelength of light. Hence we could say that the light with the least wavelength will scatter more. And the light will be scattered more. The red light will be scattered less by the air molecules since it has a larger wavelength. Hence it will travel long through the mist and fog.
Note: Since the red light has a longer wavelength and has the ability to travel long it is used in almost all dangerous situations.
The wavelength and frequency are inversely proportional to each other, if the wavelength has the greater value then the frequency value will be the least. The red light has a longer wavelength hence it has less frequency and the blue light has less wavelength so greater in frequency value.
Complete step by step solution:
To solve the question we should know which color is used for the signal to stop the vehicles. And we should also know the relation between the wavelength, frequency, and scattering of light.
The phenomenon of scattering refers to when a light ray is passed through a medium then some of the rays get absorbed by the medium and the majority of the ray gets deflected from its path and ie the rays get scattered. And this phenomenon observed is called scattering.
Now we should know what wavelength of the light refers to. The wavelength of the light can be defined as the distance between the two troughs or two crests. We should know which light has the highest wavelength and lowest wavelength. The highest wavelength is observed by red light among the visible light and the least wavelength is observed by the blue light among the visible light
Now we should establish a relation between the wavelength of the light and the scattering phenomenon.
The scattering of light is inversely proportional to the fourth power of the wavelength of light. Hence we could say that the light with the least wavelength will scatter more. And the light will be scattered more. The red light will be scattered less by the air molecules since it has a larger wavelength. Hence it will travel long through the mist and fog.
Note: Since the red light has a longer wavelength and has the ability to travel long it is used in almost all dangerous situations.
The wavelength and frequency are inversely proportional to each other, if the wavelength has the greater value then the frequency value will be the least. The red light has a longer wavelength hence it has less frequency and the blue light has less wavelength so greater in frequency value.
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