Question

In the T – 20 cricket match, Raju hit a six 10 times out of 50 balls he played. If a ball was selected at random find the probability that he would not have hit a six.

Answer 1

Hint: In this particular type of question use the concept that the total number of outcomes is equal to the total balls Raju faced and favorable number of outcomes is the difference of the total ball Raju faced and the number of balls on which he hit a six so use these concepts to reach the solution of the question.

Complete step-by-step answer:
Total balls Raju faced = 50.
Number of balls on which he hit a six = 10.
Now as we know that the probability is the ratio of the favorable number of outcomes to the total number of outcomes.
Therefore, probability (P) = $\dfrac{{{\text{favorable number of outcomes}}}}{{{\text{total number of outcomes}}}}$
Now we have to find the probability that he would not hit a six, when a ball is chosen at random.
So the total number of outcomes = total balls Raju faced = 50.
And the favorable number of outcomes is the difference of the total ball Raju faced and the number of balls on which he hit a six.
So the favorable number of outcomes = total balls Raju faced – number of balls on which he hit a six.
So the favorable number of outcomes = 50 – 10 = 40.
So the probability that he would not hit a six, when a ball is chosen at random is,
$ \Rightarrow P = \dfrac{{40}}{{50}} = \dfrac{4}{5} = 0.8$
So this is the required answer.

Note:Whenever we face such types of questions the key concept we have to remember is that always recall the formula of the probability which is stated above, so first find out the favorable number of outcomes to the total number of outcomes then divide them as above and simplify we will get the required probability.