
In the given figure, the common tangents $AB$ and $CD$ to two circles with centers $O$ and ${O}'$ intersect at E. Prove that the point $O, E\,and\,{E}'$ are collinear.
Answer
588.6k+ views
Hint: To solve the above question, we will have to join \[OA\] and \[OC\] where \[AB\] and $CD$ are common tangents to circles with center $O$ and ${O}'$ intersecting at $E$. We have to show $O,\, E,\,{E}'$ are collinear. So for that, we have to know the concept of collinear that is three or more points that lie on the same line are collinear points. Example: The points $A,B\,and\,C$ lie on the line \[m\] . So, they are collinear. Here $OA$ and $OC$ are the radii of the same circle and $\angle OAE$&$\angle OCE$ are the right angle. We will consider the four rules to prove triangle congruence. They are called the $SSS$ rule, $SAS$ rule, $ASA$ rule, and $AAS$ rule
Complete step-by-step solution:
The figure for the given problem is as follows:
In triangle $OAE$ and triangle $OCE$, we have,
$OA=OC$ (Radii of same circle)
$OE=OE$ (Common)
$\angle OAE=\angle OCE$$\left( {{90}^{\circ}} \right)$ (As the tangent is always perpendicular to the radius at the point of contact)
$\therefore \Delta OAE\cong \,\Delta OCE$
So, we have $\angle AEO=\angle CEO$ (By$CPCT$ ) (1)
Similarly we have,$\angle DE{O}'=\angle BE{O}'$ (By$CPCT$ ) (2)
NOW $\angle AEC=\angle DEB$ (Vertically opposite angles)
$\Rightarrow \dfrac{\angle AEC}{2}=\dfrac{\angle DEB}{2}$
$\Rightarrow \angle AEO=\angle DE{O}'$
$\Rightarrow \angle AEO=\angle CEO=\angle DE{O}'=\angle BE{O}'$
So, we can see that all $4\,\angle 'S$ are equal and bisected by $OE$&$O{E}'$.
So, we can see that $O, E,{O}'$ are collinear.
Hence, in this way we have proved this problem.
Note: For to prove the following problem students have to know the properties of congruence of triangles. By using this property prove the following problem. Basically, students have to keep in mind that the concept that the tangent is always perpendicular to the radius at the point of contact and prove it accordingly. Sometimes, they do a mistake by taking the right angle. So, students have to be careful about it.
Complete step-by-step solution:
The figure for the given problem is as follows:
In triangle $OAE$ and triangle $OCE$, we have,
$OA=OC$ (Radii of same circle)
$OE=OE$ (Common)
$\angle OAE=\angle OCE$$\left( {{90}^{\circ}} \right)$ (As the tangent is always perpendicular to the radius at the point of contact)
$\therefore \Delta OAE\cong \,\Delta OCE$
So, we have $\angle AEO=\angle CEO$ (By$CPCT$ ) (1)
Similarly we have,$\angle DE{O}'=\angle BE{O}'$ (By$CPCT$ ) (2)
NOW $\angle AEC=\angle DEB$ (Vertically opposite angles)
$\Rightarrow \dfrac{\angle AEC}{2}=\dfrac{\angle DEB}{2}$
$\Rightarrow \angle AEO=\angle DE{O}'$
$\Rightarrow \angle AEO=\angle CEO=\angle DE{O}'=\angle BE{O}'$
So, we can see that all $4\,\angle 'S$ are equal and bisected by $OE$&$O{E}'$.
So, we can see that $O, E,{O}'$ are collinear.
Hence, in this way we have proved this problem.
Note: For to prove the following problem students have to know the properties of congruence of triangles. By using this property prove the following problem. Basically, students have to keep in mind that the concept that the tangent is always perpendicular to the radius at the point of contact and prove it accordingly. Sometimes, they do a mistake by taking the right angle. So, students have to be careful about it.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

A moving boat is observed from the top of a 150 m high class 10 maths CBSE

