Answer
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Hint: First, join AC, BD and EF. Now, in triangle CAB, AE is the bisector of $\angle $BAC. Use the angle bisector theorem to get $\dfrac{AC}{AB}=\dfrac{CE}{BE}$. Similarly, from triangle CAD, you get $\dfrac{AC}{AD}=\dfrac{CF}{DF}$. Substitute AB = AD to get $\dfrac{AC}{AB}=\dfrac{CF}{DF}$. Equate the previous equation with this one to get $\dfrac{CE}{EB}=\dfrac{CF}{FD}$. Now, use the converse of Intercept Theorem to get the final answer.
Complete step by step answer:
In this question, we are given that ABCD is a quadrilateral in which AB = AD. The bisector of $\angle $BAC and$\angle $CAD intersect the sides BC and CD at the points E and F respectively.
We need to prove that EF || BD.
Construction: Join AC, BD and EF.
In triangle CAB, AE is the bisector of $\angle $BAC.
Now, we will use the angle bisector theorem on triangle CAB.
The Angle Bisector Theorem says that an angle bisector of a triangle will divide the opposite side into two segments that are proportional to the other two sides of the triangle.
Using the above theorem, we will get the following:
$\dfrac{AC}{AB}=\dfrac{CE}{BE}$ …(1)
Similarly, in triangle CAD, AE is the bisector of $\angle $DAC.
Now, we will use the angle bisector theorem on triangle CAB.
Using the angle bisector theorem, we will get the following:
$\dfrac{AC}{AD}=\dfrac{CF}{DF}$
Now, we are given that AB = AD. Substituting this in the above equation, we will get the following:
$\dfrac{AC}{AB}=\dfrac{CF}{DF}$ …(2)
From equations (1) and (2), we will get the following:
$\dfrac{CE}{EB}=\dfrac{CF}{FD}$
Thus, in triangle CBD, E and F divide the sides CB and CD respectively in the same ratio. Therefore, by the converse of Intercept Theorem, we have EF ∣∣ BD.
Hence proved.
Note: In this question, it is very important to know the angle bisector theorem. It is also important to know the intercept theorem. The intercept theorem states if a transversal makes equal intercepts on three or more parallel lines, then any other line cutting them will also make equal intercepts.
Complete step by step answer:
In this question, we are given that ABCD is a quadrilateral in which AB = AD. The bisector of $\angle $BAC and$\angle $CAD intersect the sides BC and CD at the points E and F respectively.
We need to prove that EF || BD.
Construction: Join AC, BD and EF.
In triangle CAB, AE is the bisector of $\angle $BAC.
Now, we will use the angle bisector theorem on triangle CAB.
The Angle Bisector Theorem says that an angle bisector of a triangle will divide the opposite side into two segments that are proportional to the other two sides of the triangle.
Using the above theorem, we will get the following:
$\dfrac{AC}{AB}=\dfrac{CE}{BE}$ …(1)
Similarly, in triangle CAD, AE is the bisector of $\angle $DAC.
Now, we will use the angle bisector theorem on triangle CAB.
Using the angle bisector theorem, we will get the following:
$\dfrac{AC}{AD}=\dfrac{CF}{DF}$
Now, we are given that AB = AD. Substituting this in the above equation, we will get the following:
$\dfrac{AC}{AB}=\dfrac{CF}{DF}$ …(2)
From equations (1) and (2), we will get the following:
$\dfrac{CE}{EB}=\dfrac{CF}{FD}$
Thus, in triangle CBD, E and F divide the sides CB and CD respectively in the same ratio. Therefore, by the converse of Intercept Theorem, we have EF ∣∣ BD.
Hence proved.
Note: In this question, it is very important to know the angle bisector theorem. It is also important to know the intercept theorem. The intercept theorem states if a transversal makes equal intercepts on three or more parallel lines, then any other line cutting them will also make equal intercepts.
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