
In the given circuit the ammeter and voltmeter are ideal and the battery of \[6V\] has internal resistance \[1\Omega \]. The reading of voltmeter and ammeter is:
A. \[zero,\dfrac{4}{3}\]
B. \[\dfrac{4}{3}V,zero\]
C. \[6V,0.1A\]
D. \[3.6V,0.6A\]
Answer
500.1k+ views
Hint: The current through the ammeter is the same current that is flowing through the circuit. The reading of the voltmeter is the same as the potential difference between the same terminals.
Formula used:
The ohm’s law is given by,
\[V = IR\]
where\[V\] is the voltage across the circuit component \[I\] is the current through the circuit and \[R\] is the resistance of the element \[R\].
Complete step by step answer:
We have given the circuit and we have to find the voltage and current through the ammeter and the voltmeter. Now, we can redraw the circuit as the following diagram given below.
So, from the figure we can see that the voltage reading of the voltmeter will be a potential drop across the two resistances. Now, we have to find the current through the circuit. To find the current, at first we have to find the total resistance of the circuit. So, net resistance across the cell is \[(3 + 3 + 3 + 1)\Omega = 10\Omega \].
So, the current through circuit is,
\[I = \dfrac{6}{{10}} = 0.6A\]
So, the potential drop across the voltmeter will be, \[V = I \times 6V\].
\[V = 0.6 \times 6V = 3.6V\]
The voltage reading of the voltmeter will be, \[3.6V\]. Now, the current through the ammeter is the same current as the circuit current. So, the current through the ammeter is, \[0.6A\]. Hence, the reading of voltmeter and ammeter is \[(3.6V,0.6A)\].
Hence, option D is the correct answer.
Note: The voltmeter is always connected in parallel to a circuit to measure the voltage across a circuit element and the ammeter is always connected in a series to measure the current across a circuit element.A voltmeter is an instrument used for measuring the voltage or potential difference between two points in an electrical circuit. The voltmeter is always connected parallel. The voltmeter is of two types: digital voltmeter and analog voltmeter.
Formula used:
The ohm’s law is given by,
\[V = IR\]
where\[V\] is the voltage across the circuit component \[I\] is the current through the circuit and \[R\] is the resistance of the element \[R\].
Complete step by step answer:
We have given the circuit and we have to find the voltage and current through the ammeter and the voltmeter. Now, we can redraw the circuit as the following diagram given below.
So, from the figure we can see that the voltage reading of the voltmeter will be a potential drop across the two resistances. Now, we have to find the current through the circuit. To find the current, at first we have to find the total resistance of the circuit. So, net resistance across the cell is \[(3 + 3 + 3 + 1)\Omega = 10\Omega \].
So, the current through circuit is,
\[I = \dfrac{6}{{10}} = 0.6A\]
So, the potential drop across the voltmeter will be, \[V = I \times 6V\].
\[V = 0.6 \times 6V = 3.6V\]
The voltage reading of the voltmeter will be, \[3.6V\]. Now, the current through the ammeter is the same current as the circuit current. So, the current through the ammeter is, \[0.6A\]. Hence, the reading of voltmeter and ammeter is \[(3.6V,0.6A)\].
Hence, option D is the correct answer.
Note: The voltmeter is always connected in parallel to a circuit to measure the voltage across a circuit element and the ammeter is always connected in a series to measure the current across a circuit element.A voltmeter is an instrument used for measuring the voltage or potential difference between two points in an electrical circuit. The voltmeter is always connected parallel. The voltmeter is of two types: digital voltmeter and analog voltmeter.
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