In the electrolysis of $AgN{O_3}$ solution, $0.7\,of\,Ag$is deposited after a certain period of time. Calculate the quantity of electricity required in coulomb. (Molar mass of $Ag$ is$107.9gmo{l^{ - 1}}$ ).
Answer
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Hint: To solve this problem, firstly we have to understand about mole, molar mass, mole concept and electrochemistry and the concepts behind them, and then we will be calculating the solution asked in the question, and hence we will be approaching our answer.
Complete step by step solution:
Mole concept: Mole concept is the convenient method for expressing the amount of substance. In chemistry measurements can be divided into two parts, the numerical magnitude and the units. for example, when a mass of a ball is measured $2Kg$ . The magnitude is $'2'$ and the unit is$'Kg'$ .
Mole: It is the amount of a substance that contains exactly$6.02214076 \times {10^{23}}$ elementary entities of the given substance.
Molar mass - It is defined as the total mass of one mole of a substance. It is represented in grams per mole, however the S.I unit is$Kg/mol$ .
Electrochemistry - It is the branch of science which deals with production of electricity from the energy released during spontaneous chemical reactions and use of that energy to carry out non- spontaneous chemical reactions.
Importance of Electrochemistry
Production of metals like $Na,\,Mg\,,Ca,Al$
Electroplating
Purification of metals.
Given: Mass of $Ag$ deposited$ = \,0.7g$
Molar mass of $Ag$ $ = \,107.9gmo{l^{ - 1}}$
Quantity of electricity,$Q = \,?$
The half- cell reaction is
$A{g^ + }\left( {aq} \right) + \,{e^ - } \to Ag\left( s \right)$
$\therefore $ 1 mole of $Ag$ produced $ = 107.9g\,Ag$ requires 1 mole of electrons.
$\therefore 0.7g\,Ag$ will require,
$ = \dfrac{{Mass\,of\,Ag}}{{Molar\,mass\,of\,Ag}}$
$ = \dfrac{{0.7}}{{107.9}} = 6.49 \times {10^{ - 3}}mol\,of\,Ag$
$\therefore \,1$ mole electron carries $96500C$ Charge.
$\therefore 6.49 \times {10^{ - 3}}mol\,$ of electrons will carry.
$Q = \dfrac{{96500 \times 6.49 \times {{10}^{ - 3}}}}{1}$
$ = 626$ Coulombs.
Note - The charge is the property of matter because of which it experiences the force of attraction and repulsion whereas the current is the rate of flow of charge particle called as electrons. The charge experiences the force only in applied electric field whereas the current experience both I, electric and magnetic field.
They both are interrelated to each other.
Complete step by step solution:
Mole concept: Mole concept is the convenient method for expressing the amount of substance. In chemistry measurements can be divided into two parts, the numerical magnitude and the units. for example, when a mass of a ball is measured $2Kg$ . The magnitude is $'2'$ and the unit is$'Kg'$ .
Mole: It is the amount of a substance that contains exactly$6.02214076 \times {10^{23}}$ elementary entities of the given substance.
Molar mass - It is defined as the total mass of one mole of a substance. It is represented in grams per mole, however the S.I unit is$Kg/mol$ .
Electrochemistry - It is the branch of science which deals with production of electricity from the energy released during spontaneous chemical reactions and use of that energy to carry out non- spontaneous chemical reactions.
Importance of Electrochemistry
Production of metals like $Na,\,Mg\,,Ca,Al$
Electroplating
Purification of metals.
Given: Mass of $Ag$ deposited$ = \,0.7g$
Molar mass of $Ag$ $ = \,107.9gmo{l^{ - 1}}$
Quantity of electricity,$Q = \,?$
The half- cell reaction is
$A{g^ + }\left( {aq} \right) + \,{e^ - } \to Ag\left( s \right)$
$\therefore $ 1 mole of $Ag$ produced $ = 107.9g\,Ag$ requires 1 mole of electrons.
$\therefore 0.7g\,Ag$ will require,
$ = \dfrac{{Mass\,of\,Ag}}{{Molar\,mass\,of\,Ag}}$
$ = \dfrac{{0.7}}{{107.9}} = 6.49 \times {10^{ - 3}}mol\,of\,Ag$
$\therefore \,1$ mole electron carries $96500C$ Charge.
$\therefore 6.49 \times {10^{ - 3}}mol\,$ of electrons will carry.
$Q = \dfrac{{96500 \times 6.49 \times {{10}^{ - 3}}}}{1}$
$ = 626$ Coulombs.
Note - The charge is the property of matter because of which it experiences the force of attraction and repulsion whereas the current is the rate of flow of charge particle called as electrons. The charge experiences the force only in applied electric field whereas the current experience both I, electric and magnetic field.
They both are interrelated to each other.
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