Question

In the below equation, the substance undergoing oxidation is
$Pb{O_2} + 4HCl \to PbC{l_2} + 2{H_2}O + C{l_2}$
 A.Lead dioxide
 B.Hydrochloric acid
 C.Chlorine gas
 D.Lead chloride

Answer 1

Hint: We have to know that, the oxidation state, likewise alluded to as the measure of oxidation, characterizes a synthetic compound's level of oxidation (loss of electrons) of a molecule. Antoine Lavoisier originally utilized the term oxidation to portray a substance's response with oxygen.

Complete answer:
We have to know that oxidation is a compound cycle, which can be clarified by following four places of perspectives. They are as far as oxygen move, oxidation move, hydrogen move, electron move.
Oxidation as far as oxygen moves is gain or oxygen.
Oxidation as far as oxidation number is an increment in the oxidation state or oxidation number of an iota in a response. Oxidation number characterizes the level of oxidation of an iota in a substance compound. For instance, the oxidation condition of sodium is expanding from $0$to $ - 1$. In this manner, oxidation is occurring and sodium is getting oxidized.
Oxidation as far as hydrogen moves, it tends to be characterized as loss of hydrogen.
Oxidation as far as electrons move is loss of electrons. For instance, magnesium is losing two electrons and getting oxidized to frame magnesium oxide.
In the given balanced chemical equation,
$Pb{O_2} + 4HCl \to PbC{l_2} + 2{H_2}O + C{l_2}$
Presently considering the oxidation condition of chlorine in$HCl$ is $ - 1$. While the oxidation condition of chlorine in $C{l_2}$is $0$. So the oxidation condition of chlorine
increases. So $HCl$ is going through oxidation.

The correct option is (B).

Note:
We have to know that oxidation-decrease (redox) responses are critical on the ground that they are the principal characteristic or organic and fake fuel sources on this planet. Oxidation of atoms normally delivers a lot of energy by eliminating hydrogen and supplanting it with oxygen.