
In how many ways can the letter of the word ‘STORY’ be arranged so that T and Y are always together.
A) 24
B) 30
C) 10
D) 48
Answer
583.2k+ views
Hint:In this problem we will arrange all the letters by taking T and Y as a single unit and after that we will find out the total possible arrangements of these two letters T and Y.
Complete step-by-step answer:
Given: we have given the word ‘STORY’ and out of this word we have to find out that in how many ways can the word ‘STORY’ be arranged while the letter T and V come together.
First, find the letters available in the given word which are 5.
Now, we will take the letter T and Y as a single unit.
So, the total number of letters present in the given word after taking the letter T and Y as a single unit.
Now, that means there are 4 letters in the word.
So, total arrangements present in it is given by ${\text{N}}!$
Here ${\text{N}}$is the total units which are 4.
Then, substitute the value of ${\text{N}}$ in ${\text{N}}!$
$
{\text{N}}! = 4! \\
\Rightarrow 4 \times 3 \times 2 \times 1 \\
\Rightarrow 24 \\
$
And now, we can arrange letters T and Y by $2!$ ways.
So, to get the total arrangements , we will multiply both the situations.
So, total arrangements is ,
Arrangements of 4 letters $ \times $arrangements of two letter T and Y.
That is ,$4! \times 2!$
Now, solve the equation.
$ = 24 \times 2 = 48$
So, the total ways of arrangements are 48 ways.
Hence, the option D is the correct answer.
Note:Make sure that you consider the alphabets T and Y as one single unit. Considering them as two separate units will lead to wrong answers. Also remember to see that the position of the alphabets is proper in such problems.
Complete step-by-step answer:
Given: we have given the word ‘STORY’ and out of this word we have to find out that in how many ways can the word ‘STORY’ be arranged while the letter T and V come together.
First, find the letters available in the given word which are 5.
Now, we will take the letter T and Y as a single unit.
So, the total number of letters present in the given word after taking the letter T and Y as a single unit.
Now, that means there are 4 letters in the word.
So, total arrangements present in it is given by ${\text{N}}!$
Here ${\text{N}}$is the total units which are 4.
Then, substitute the value of ${\text{N}}$ in ${\text{N}}!$
$
{\text{N}}! = 4! \\
\Rightarrow 4 \times 3 \times 2 \times 1 \\
\Rightarrow 24 \\
$
And now, we can arrange letters T and Y by $2!$ ways.
So, to get the total arrangements , we will multiply both the situations.
So, total arrangements is ,
Arrangements of 4 letters $ \times $arrangements of two letter T and Y.
That is ,$4! \times 2!$
Now, solve the equation.
$ = 24 \times 2 = 48$
So, the total ways of arrangements are 48 ways.
Hence, the option D is the correct answer.
Note:Make sure that you consider the alphabets T and Y as one single unit. Considering them as two separate units will lead to wrong answers. Also remember to see that the position of the alphabets is proper in such problems.
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