Question

In garden pea, round shape is dominant over wrinkled shape. A pea plant heterozygous for round shape of seed is self and 1600 seeds produced during the cross are subsequently germinated. How many offspring will have parental phenotype?
A) 1600
B) 800
C) 400
D) 1200

Answer 1

Hint:Mendel examined the inheritance of seven unique characteristics in peas, including stature, bloom shading, seed shading, and seed shape. To do as such, he originally settled pea lines with two distinct types of a component, for example, tall versus short tallness. He developed these lines for ages until they were unadulterated rearing (consistently created posterity indistinguishable from the parent), at that point reproduced them to one another and saw how the qualities were acquired.

Complete Answer:
In 1865, Mendel introduced the consequences of his trials with almost 30,000 pea plants to the neighborhood Natural History Society. In light of the examples he observed , the tallying information he gathered, and a numerical investigation of his outcomes, Mendel proposed a model of inheritance in which:
>Characteristics, for example, flower colour , plant tallness, and seed shape were constrained by sets of heritable elements that came in various versions.
>One adaptation of a factor (the predominant structure) could veil the presence of another rendition (the latent structure).
>The two combined components isolated during gamete creation, with the end goal that every gamete (sperm or egg) arbitrarily got only one factor. So, As the pea plant is heterozygous for round shape, its genotype would be Rr.
->Parents- : Rr x Rr
->Offspring: rr
Phenotypically, the ratio will be 3:1. i.e., just rr cultivating will show wrinkled phenotype, rest will show round shape. At the point when the absolute number of seed is 1600 so
->1200 - Round shape (RR, Rr)
->400 - Wrinkled (rr).

Hence the right answer is option D (1200).

Note:Mendel also proposed that the components controlling various qualities were acquired autonomously of each other.