In fig if AB$||$CD, CD$||$EF and $y:z = 3:7$ find $x$
Answer
584.1k+ views
Hint: This sum involves application of properties of lines. The student has to make use of the properties like Corresponding Angles, Alternate Angles and sum of interior angles on the same side of the transversal is ${180^ \circ }$. This sum is extremely to solve and should involve no margin of error.
Complete answer:
From the figure we can see that it is given $\dfrac{y}{z} = \dfrac{3}{7}$
$\therefore y = \dfrac{3}{7}z$
Let $\angle CON = P$
Given CD$||$EF,
We can Say that $P = z$, Since they are Alternate Interior Angles
Also from the figure we can say
$\Rightarrow$ $y + P = {180^ \circ }$ Using the property i.e. sum of interior angles on same side of transversal is ${180^ \circ }$.
Now we can say that
$\Rightarrow$$y + z = {180^ \circ }$,
Also we know,
$\therefore y = \dfrac{3}{7}z$,
$\Rightarrow$$\dfrac{3}{7}z + z = {180^ \circ }$
$\therefore z = \dfrac{7}{{10}} \times {180^ \circ } = {126^ \circ }$
Putting $z = {126^ \circ }$,we get the value of $y$
$\therefore y = \dfrac{3}{7} \times 126 = {54^ \circ }$.
Also we can say that
$\Rightarrow$ $x + y = {180^ \circ }$,
Using the property i.e. sum of interior angles on the same side of transversal is ${180^ \circ }$.
$\therefore x = {180^ \circ } - {54^ \circ }$
$\therefore x = {126^ \circ }$
Note: It is important to note that the sums on geometry can be solved only if the student is well versed with the properties of the figures. Also sometimes the corollary of the properties can be used to solve the problems, so it is important to thoroughly study the properties.
Complete answer:
From the figure we can see that it is given $\dfrac{y}{z} = \dfrac{3}{7}$
$\therefore y = \dfrac{3}{7}z$
Let $\angle CON = P$
Given CD$||$EF,
We can Say that $P = z$, Since they are Alternate Interior Angles
Also from the figure we can say
$\Rightarrow$ $y + P = {180^ \circ }$ Using the property i.e. sum of interior angles on same side of transversal is ${180^ \circ }$.
Now we can say that
$\Rightarrow$$y + z = {180^ \circ }$,
Also we know,
$\therefore y = \dfrac{3}{7}z$,
$\Rightarrow$$\dfrac{3}{7}z + z = {180^ \circ }$
$\therefore z = \dfrac{7}{{10}} \times {180^ \circ } = {126^ \circ }$
Putting $z = {126^ \circ }$,we get the value of $y$
$\therefore y = \dfrac{3}{7} \times 126 = {54^ \circ }$.
Also we can say that
$\Rightarrow$ $x + y = {180^ \circ }$,
Using the property i.e. sum of interior angles on the same side of transversal is ${180^ \circ }$.
$\therefore x = {180^ \circ } - {54^ \circ }$
$\therefore x = {126^ \circ }$
Note: It is important to note that the sums on geometry can be solved only if the student is well versed with the properties of the figures. Also sometimes the corollary of the properties can be used to solve the problems, so it is important to thoroughly study the properties.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Discuss the various forms of bacteria class 11 biology CBSE

