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In ClO2, unpaired electron reside in:
A.sp2 hybridised orbital
B. sp3 hybridised orbital
C. p orbital
D. d orbital

Answer
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Hint:To solve this kind of problem, we need to find out the hybridisation of the molecule. Then the hybridised orbital corresponding to the hybridisation will be the orbital in which the unpaired electron resides.

Complete step by step answer:
We know that the electronic configuration of chlorine is 1s22s22p63s23p5. The outermost shell contains seven electrons which participates in hybridisation. Out of the seven electrons in the valence shell, two pairs of electrons are bonded with two oxygen atoms to form double bonds and one pair of electrons exist as lone pairs. The remaining one unpaired electron will exist as separately. So, the steric number of this molecule is four since two bonded pairs, one lone pair and one odd electron. Therefore, the hybridisation of the molecule will be sp3. So, the unpaired electron will reside in one of the sp3 hybridised orbits. Also, the geometry of the molecule will be tetrahedral.

Additional Information:
The chlorine dioxide has many uses like bleaching, disinfection of drinking water. This molecule will be used to treat the drinking water in order to destroy the taste and odour due to phenolic compounds.



Note:ClO2 is very rarely exist and highly unstable. Therefore, it is a very reactive molecule. Normally, the molecule exists as ClO2 with two unpaired electrons. The bond angle of ClO2 will be greater than the bond angle of ClO2 since the repulsion will be greater in the case of ClO2.
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