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# In an objective type’s paper of $150$ questions; John got $80\%$ correct answers and Mohan got $64\%$ correct answers. What percentage are Mohan’s correct answers to John's correct answers?A. $100\%$B. $16\%$C. $64\%$D. $80\%$

Last updated date: 20th Jun 2024
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Hint: First we have to find marks on both Mohan and John, then we have to calculate percentage from Mohan’s to John.
Finally we get the required answer.

Formula used: Percentage ${\text{ = }}\dfrac{{{\text{value}}}}{{{\text{Total value}}}}{{ \times 100}}$
Value ${\text{ = }}\dfrac{{{{Percentage \times Total value}}}}{{{\text{100}}}}$
This formula helps to get the required result.

It is given that the total number of questions in an objective type paper which is $150$
Percentage of Mohan’s correct answers $= 64\%$
Percentage of john’s correct answers $= 80\%$
First, we have to find john’s marks,
Number of correct answers got by John is equal to ${\text{ = }}\dfrac{{{{Percentage \times Total value}}}}{{{\text{100}}}}$
Now substitute the values we get,
$\dfrac{{80}}{{100}} \times 150 = 120$
Hence, John got $120$ marks
Next, we have to find Mohan’s marks,
Number of correct answers got by Mohan is equal to ${\text{ = }}\dfrac{{{{Percentage \times Total value}}}}{{{\text{100}}}}$
Now substitute the values we get,
$\dfrac{{64}}{{100}} \times 150 = 96$
Hence, Mohan got $96$ marks
Now, we find Percentage of Mohan’s correct answers to John’s correct answers,
Which can be done by,
$\dfrac{{{\text{Mohan's correct answer}}}}{{{\text{John's correct answer}}}}{{ \times 100}}$
Now, substitute the obtained values of Mohan’s correct answer and John’s correct answer in above formula.
$\dfrac{{96}}{{120}} \times 100 = 80\%$

So, the Percentage of Mohan’s correct answers to John’s correct answers is $80\%$

Note: In this question, we have alternative method as follows:
Total objective type question $= 150$
Percentage of Mohan’s correct answers $= 64\%$
Percentage of john’s correct answers $= 80\%$
Now, we calculate the percentage of correct answers,
Percentage of correct answer from that of Mohan to John is,
Which can be done by,
$\dfrac{{{\text{Mohan's percentage}}}}{{{\text{John's percentage}}}}{{ \times 100}}$
Substitute the values we get,
$\dfrac{{64}}{{80}} \times 100 = 80\%$
$\therefore$ The Percentage of Mohan’s correct answers to John’s correct answers is $80\%$