Question

In a world cup final match against Srilanka, for six times Sachin Tendulkar hits a six out of $30$ balls he plays. What is the probability that in a given throw the ball does not hit a six?
${
  A.\dfrac{1}{4} \\
  B.\dfrac{5}{4} \\
  C.\dfrac{4}{5} \\
  D.\dfrac{3}{4} \\
} $

Answer 1

Hint: First of all, read the question carefully so that you can understand the given information & what they have asked for as an answer in the question. To solve this type of question, first of all we will have to divide the favorable cases by the total no. of balls & simplify it to the simplest possible fraction.

Complete step-by-step answer:
It is given here that the total no. of balls played by Sachin Tendulkar is 30. Out of those 30 balls, he hit 6 six out of 30 balls.
To find: We have to find the probability that Sachin doesn’t hit six.
To find this the formula which we will have to apply is:
$\therefore $
$ = $And then we will subtract P(A) from 1 to get the ultimate answer.
      Let A be the event that the ball is thrown hits six.
   n(A) represents no. of balls thrown hit six,
& Let S be the event that the ball thrown hits six
     n(S) represents the total no. of balls played by Sachin Tendulkar.
Now the known values of this are$ = \dfrac{{24}}{{30}}$
Now we have to find $ = \dfrac{4}{5}$
Therefore, the probability that the ball thrown hits six, $\therefore $
$30$
Hence the probability that the ball thrown does not hit six is P(A′).
So, to get we will have to subtract P(A) from 1,
  $\therefore $ $30 - 6 = 24$
Hence, the probability is $\dfrac{4}{5}$ when the ball does not hit six.

Note: Probability of any event will always lie between 0 and 1. The sum of probabilities of an event to occur and that event to not occur will always be equal to 0.