
In a two digit number, the digit at ten’s place is 4 and the product of the two digit is 4 times greater than the value of the digit in the ten’s place. What is the two digit number?
A. 42
B. 48
C. 44
D. 84
Answer
617.7k+ views
Hint: The digits in the unit and the tens place of the two digit number are to be found using the conditions provided by creating the necessary equations and solving them.
Complete step-by-step answer:
It is given that the no. is two digit.
Let (xy) be the two digit number such that (x) is in ten’s place and (y) is in one’s place.
Now it is given that the digit in ten’s place is 4, and we know that (x) is in ten’s place.
$ \Rightarrow x = 4$
Now it is given that the product of two digits (i.e. xy) is 4 times greater than the value of digit in the ten’s place.
$ \Rightarrow x \times y = 4 \times x$
Now we know that the value of x is 4
$ \Rightarrow 4 \times y = 4 \times 4$
\[ \Rightarrow y = \dfrac{{16}}{4}\]
$\Rightarrow y = 4$
So the required no. is (xy)
i.e. 44
Therefore the correct answer is option C.
Note: In this question we firstly analyze what is given to use and then write the relation between the product of the number and the digit at ten’s place and by solving the equations, we get our answer.
Complete step-by-step answer:
It is given that the no. is two digit.
Let (xy) be the two digit number such that (x) is in ten’s place and (y) is in one’s place.
Now it is given that the digit in ten’s place is 4, and we know that (x) is in ten’s place.
$ \Rightarrow x = 4$
Now it is given that the product of two digits (i.e. xy) is 4 times greater than the value of digit in the ten’s place.
$ \Rightarrow x \times y = 4 \times x$
Now we know that the value of x is 4
$ \Rightarrow 4 \times y = 4 \times 4$
\[ \Rightarrow y = \dfrac{{16}}{4}\]
$\Rightarrow y = 4$
So the required no. is (xy)
i.e. 44
Therefore the correct answer is option C.
Note: In this question we firstly analyze what is given to use and then write the relation between the product of the number and the digit at ten’s place and by solving the equations, we get our answer.
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