Question

In a school, the strength is $ 8th,9th $ and $ 10th $ standards are respectively $ 48,42 $ and $ 60 $ . Find the least number of books required to be distributed equally among the classes of $ 8th,9th $ and $ 10th $ standard.

Answer 1

Hint: As we know that the above given question is a word problem. A problem is a mathematical question written as one sentence or more describing a real life scenario where that problem needs to be solved by the way of mathematical calculation. We can solve the given problem by applying the method of mathematical numbers as least or highest number of multiple required.

Complete step-by-step answer:
We need to first understand the requirement of the question which is the least number of books which means that we have to calculate the L.C.M of numbers.
Here $ 48,42 $ and $ 60 $ can be factorised as follows:
 $ 48 = 2 \times 2 \times 2 \times 2 \times 3 $
 $ 42 = 2 \times 3 \times 7 $ and $ 60 = 2 \times 2 \times 3 \times 5 $ .
We know that the LCM is the least common multiple, so the LCM of $ 48,42 $ and $ 60 $ is $ LCM = 2 \times 2 \times 2 \times 2 \times 3 \times 7 \times 5 = 1680 $ .
Hence $ 1680 $ books are required to be distributed equally among the classes of $ 8th,9th $ and $ 10th $ standard.
So, the correct answer is “ $ 1680 $ ”.

Note: We should always be careful what the question is asking i.e. is it asking the least number of books or the highest number of books since both are very different concepts. Based on the requirement and by observing all the necessary information that is already available in the question we gather the information and then create an equation or by unitary method whichever is applicable, then we solve the problem and then verify the answer by putting the value in the problem and see whether we get the same answer or not.