
In a sample of pitchblende, the atomic ratio of \[P{{b}^{206}}:{{U}^{238}}\] is 0.23:1. Calculate the age of the mineral if half life of uranium is \[4.5\times {{10}^{9}}\]year. All lead originated from uranium.
Answer
585.9k+ views
Hint: Nuclear chemistry is the chemistry involving radioactive substances. Nuclear reactions are usually first order reactions. Decay constant or radioactive constant is the ratio of no. of decay per minute of radioactive substance in the sample to the total number of particles present in the sample.
Complete step by step solution:
The radioactive properties of uranium can be used to determine the age of minerals and rocks.
The equation to find half life of a radioactive material is
\[{{t}_{{}^{1}/{}_{2}}}=\dfrac{\log 2}{\lambda }=\dfrac{0.693}{\lambda }\], where \[\lambda \] is the disintegration constant.
In the question half life of the reaction is given. So, we can find the value of disintegration constant\[\lambda \] from the equation given above. Half life of the reaction is \[{{t}_{\dfrac{1}{2}}}=4.5\times {{10}^{9}}years\].
Let us substitute these values in the above equation.
\[\lambda =\dfrac{0.693}{4.5\times {{10}^{9}}}=0.154\times {{10}^{-9}}yea{{r}^{-1}}\]
Now consider the first order equation for the disintegration constant, which is
\[\lambda =\dfrac{2.303}{t}\log \left( \dfrac{{{N}_{0}}}{N} \right)\]--(i), where \[{{N}_{0}}\] is the initial amount of uranium present in the reaction and \[N\]is the amount of uranium present at time t.
It is given in the question, that the ratio of initial amount of uranium\[{{N}_{0}}\] (which is \[{{U}^{238}}\]) and the amount at time t \[N\]( which is\[P{{b}^{206}}\]) is : \[\dfrac{{{N}_{0}}}{N}=\dfrac{{{U}^{238}}}{P{{b}^{206}}}=\dfrac{1}{0.23}\]
So, let us substitute all the values in equation (i) and we get
\[t=\dfrac{2.303}{0.154\times {{10}^{-9}}}\log \left( \dfrac{1}{0.23} \right)\]
\[t=0.6381\times 14.954\times {{10}^{9}}=9.541\times {{10}^{9}}years\]
Therefore, the age of the mineral is \[9.541\times {{10}^{9}}years\].
Additional Information: Uranium disintegrated to give a stable Lead. The half life of Uranium is greater than all the other radioactive elements. We know radioactive decay is a first order reaction, but the rate of the reaction depends on the concentration of one reactant. It is not affected by the factors which affect chemical reactions, i.e. the rate of the reaction does not depend on the temperature, pressure or any other physical determinants. We can also say that radioactive decay is an exponential decay function, which means that if more numbers of atoms are present, the decay rate increases.
Note: The ratio given in the question is in the form amount of uranium present a time t to the initial concentration of uranium. So while substituting the values we need to check it properly.
Complete step by step solution:
The radioactive properties of uranium can be used to determine the age of minerals and rocks.
The equation to find half life of a radioactive material is
\[{{t}_{{}^{1}/{}_{2}}}=\dfrac{\log 2}{\lambda }=\dfrac{0.693}{\lambda }\], where \[\lambda \] is the disintegration constant.
In the question half life of the reaction is given. So, we can find the value of disintegration constant\[\lambda \] from the equation given above. Half life of the reaction is \[{{t}_{\dfrac{1}{2}}}=4.5\times {{10}^{9}}years\].
Let us substitute these values in the above equation.
\[\lambda =\dfrac{0.693}{4.5\times {{10}^{9}}}=0.154\times {{10}^{-9}}yea{{r}^{-1}}\]
Now consider the first order equation for the disintegration constant, which is
\[\lambda =\dfrac{2.303}{t}\log \left( \dfrac{{{N}_{0}}}{N} \right)\]--(i), where \[{{N}_{0}}\] is the initial amount of uranium present in the reaction and \[N\]is the amount of uranium present at time t.
It is given in the question, that the ratio of initial amount of uranium\[{{N}_{0}}\] (which is \[{{U}^{238}}\]) and the amount at time t \[N\]( which is\[P{{b}^{206}}\]) is : \[\dfrac{{{N}_{0}}}{N}=\dfrac{{{U}^{238}}}{P{{b}^{206}}}=\dfrac{1}{0.23}\]
So, let us substitute all the values in equation (i) and we get
\[t=\dfrac{2.303}{0.154\times {{10}^{-9}}}\log \left( \dfrac{1}{0.23} \right)\]
\[t=0.6381\times 14.954\times {{10}^{9}}=9.541\times {{10}^{9}}years\]
Therefore, the age of the mineral is \[9.541\times {{10}^{9}}years\].
Additional Information: Uranium disintegrated to give a stable Lead. The half life of Uranium is greater than all the other radioactive elements. We know radioactive decay is a first order reaction, but the rate of the reaction depends on the concentration of one reactant. It is not affected by the factors which affect chemical reactions, i.e. the rate of the reaction does not depend on the temperature, pressure or any other physical determinants. We can also say that radioactive decay is an exponential decay function, which means that if more numbers of atoms are present, the decay rate increases.
Note: The ratio given in the question is in the form amount of uranium present a time t to the initial concentration of uranium. So while substituting the values we need to check it properly.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

State the laws of reflection of light

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Which one of the following is not a method of soil class 11 biology CBSE

