In a quiz, team A scored -40, 10, 0 and team B scored 10, 0, and -40 in three successive rounds. Which team scored more? Can we say that we can add integers in any order?
Hint: The total score of a team is the sum of scores of each individual round. Simply add the individual scores round to get the final score of each team.
Complete step-by-step answer: Now the scores of team A in first round, second round and the third round is -40, 10 and 0 respectively, Hence the total score of team A by the end of the quiz will be -40 + 10 + 0 = -30……………….. (1)
Now the scores of team B in first round, second round and the third round is 10, 0 and -40 respectively, Hence the total score of team B by the end of the quiz will be 10 + 0 -40 = -30……………….. (2)
Clearly from equation (1) and equation (2) we can say that the total score after the end of the quiz for team A and team B are equal that is -30.
Hence no team scored more, both were at equal scores at the end of the quiz.
Yes, we can add integers in any order as it is also observable from above that we have added eventually the same numbers that is -40, 0 and 10 in different orders as they were the different round scores for team A and B, but still their addition comes up to be the same, although they were added in a different order.
Hence the statement that “Can we add integers in any order is absolutely true.”
Note: Whenever we face such type of problems always remember that the scores which are obtained in the individual rounds eventually gets added up to form the final score after the quiz and priority operation happens in case of different operators however if we are just performing the same operation that is adding than the order of integers doesn’t matter.
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