
In a game of angry birds, the bluebird is projected with an angle of ${60^ \circ }$ with a velocity of $6m/s$. After reaching the highest point, the bird splits up into three birds of masses in ratio $2:1:1$. Amongst the three birds, the heaviest bird falls vertically downward with velocity $15m/s$ and one bird travels straight. The velocity of the third bird will be:
$\left( A \right){\text{ 9i + 4j}}$
$\left( B \right){\text{ 9i + 30}}{\text{.44j}}$
$\left( C \right){\text{ 3i - 6j}}$
$\left( D \right){\text{ 33}}{\text{.44i + 15}}{\text{.22j}}$
Answer
568.8k+ views
Hint
Since we have to find the velocity of the bird. So for this, we have to see the initial momentum and the final momentum. And after equating both the equations we would be able to calculate the velocity of the bird. Also, the angle subtended by the bird with the velocity will be in cosine form.
Complete step by step answer
In the given question the bird is projected with an angle of ${60^ \circ }$ and also it is given that the velocity at that time is$6m/s$.
So at the highest point, the velocity will be${V_0}\cos \theta $
Where${V_0}$the velocity at is the highest point and $\cos \theta $ is the angle subtended between them.
So by putting the values and solving the above solution, we get
$ \Rightarrow 6 \times {\text{ cos}}\theta $
$ \Rightarrow 6 \times {\text{ }}\dfrac{1}{2}$
$ \Rightarrow 3m/s$
$ \Rightarrow 3i$
Equating the initial momentum and the final momentum, we get
$ \Rightarrow {P_i} = {P_f}$; Where ${P_i}$is the Initial momentum and ${P_f}$is the Final momentum.
So,
$ \Rightarrow \left( {2x + x + x} \right) \times 3i = - \left( {2x} \right) \times 15.22j + x \times 3i + x\left( {Ai + Bj} \right)$
On solving the above equation, we get
$ \Rightarrow 4 \times 3i = - 2 \times 15.22j + 3i + \left( {Ai + Bj} \right)$
On further solving
$ \Rightarrow 9i + 30.44j = \left( {Ai + Bj} \right)$
$9i + 30.44j$ Is the required velocity and Hence Option (B) will be the correct answer.
Note
The parabolic flight of a projectile, projectile motion on inclined planes. An object that's on the wing once being thrown is called a projectile. As an example, if you throw a ball up in the air at an angle apart from zero degree with the vertical, it follows a recursive path that is named its trajectory. It becomes easier to investigate the trail of a projectile if we tend to create the subsequent two assumptions:
The free-fall acceleration g is constant over the vary of motion and is directed downward, and The impact of air resistance is negligible. With these assumptions, we discover that the flight of a projectile is often a parabola that may be a version of a plot of a polynomial like this.
Since we have to find the velocity of the bird. So for this, we have to see the initial momentum and the final momentum. And after equating both the equations we would be able to calculate the velocity of the bird. Also, the angle subtended by the bird with the velocity will be in cosine form.
Complete step by step answer
In the given question the bird is projected with an angle of ${60^ \circ }$ and also it is given that the velocity at that time is$6m/s$.
So at the highest point, the velocity will be${V_0}\cos \theta $
Where${V_0}$the velocity at is the highest point and $\cos \theta $ is the angle subtended between them.
So by putting the values and solving the above solution, we get
$ \Rightarrow 6 \times {\text{ cos}}\theta $
$ \Rightarrow 6 \times {\text{ }}\dfrac{1}{2}$
$ \Rightarrow 3m/s$
$ \Rightarrow 3i$
Equating the initial momentum and the final momentum, we get
$ \Rightarrow {P_i} = {P_f}$; Where ${P_i}$is the Initial momentum and ${P_f}$is the Final momentum.
So,
$ \Rightarrow \left( {2x + x + x} \right) \times 3i = - \left( {2x} \right) \times 15.22j + x \times 3i + x\left( {Ai + Bj} \right)$
On solving the above equation, we get
$ \Rightarrow 4 \times 3i = - 2 \times 15.22j + 3i + \left( {Ai + Bj} \right)$
On further solving
$ \Rightarrow 9i + 30.44j = \left( {Ai + Bj} \right)$
$9i + 30.44j$ Is the required velocity and Hence Option (B) will be the correct answer.
Note
The parabolic flight of a projectile, projectile motion on inclined planes. An object that's on the wing once being thrown is called a projectile. As an example, if you throw a ball up in the air at an angle apart from zero degree with the vertical, it follows a recursive path that is named its trajectory. It becomes easier to investigate the trail of a projectile if we tend to create the subsequent two assumptions:
The free-fall acceleration g is constant over the vary of motion and is directed downward, and The impact of air resistance is negligible. With these assumptions, we discover that the flight of a projectile is often a parabola that may be a version of a plot of a polynomial like this.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is Environment class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

How many squares are there in a chess board A 1296 class 11 maths CBSE

Distinguish between verbal and nonverbal communica class 11 english CBSE

The equivalent weight of Mohrs salt FeSO4 NH42SO4 6H2O class 11 chemistry CBSE

