Question

In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C is
A) 8 points
B) 10 Points
C) 14 points
D) 40 points

Answer 1

Hint: Initially A, B, C have 100 points each. If A can score 100 points and A can give 20 points to B then B
 can score (100-20) points and A can give 28 points to C then C can score (100-28) points.

Complete step by step solution:
According to given condition in the question:
In a game of 100 points,
So, A can scores 100 points,
A can give 20 points to B then B can score$\left( {100 - 20} \right) = 80$points
If A can give 28 points to C then C can score (100-28) points
And C can score $\left( {100 - 28} \right) = 72$points
Therefore, when B scores 80 points, C scores 72 points
And when B scores 100 points, C scores $\dfrac{{72}}{{80}} \times 100 = 90$points
i.e., in a game of 100 points, B can give C$\left( {100 - 90} \right) = 10$points

Then the correct answer is option B.

Note:
we have to take all the values very carefully if any of the values are false then the whole question will be wrong. So, we have to read the question two times carefully.