
In a cricket league match , there are both male and female members . If m is the average age of male members and f is the average age of female members , a is the total average age and $65$ percent of the leagues members are male , then which one of the following statements relate about m , f and a ?
A - If m < f , then $a > \dfrac{{m + f}}{2}$
B - If m > f , then $a < \dfrac{{m + f}}{2}$
C - If m < f , then $a < \dfrac{{m + f}}{2}$
D - $a = \dfrac{{m + f}}{2}$
Answer
569.7k+ views
Hint:
First let us consider that the number of person in the cricket league is $100$ Use the average formula that is = $\dfrac{{{\text{Sum of ages }}}}{{{\text{Total number of person}}}}$ hence Sum of male ages $ = m \times 65$ and Sum of female ages $ = f \times 35$ from here a = $\dfrac{{m \times 65 + f \times 35}}{{100}}$ now try insert $\dfrac{{m + f}}{2}$ in this equation because all options are given in this form after that compare it with options.
Complete step by step solution:
As we know that the average of any given data is,
= $\dfrac{{{\text{Sum of ages }}}}{{{\text{Total number of person}}}}$
So let us consider that the number of person in the cricket league is $100$ and it is given that the $65$ percent of the leagues members are male
Hence $65$ person are male and $35$ person are female ,
As it is given that m is the average of the male person , and total number of male is $65$
therefore m = $\dfrac{{{\text{Sum of male ages }}}}{{{\text{Total number of male person}}}}$
Sum of male ages $ = m \times 65$
As it is given that f is the average of the female person , and total number of male is $35$
therefore f = $\dfrac{{{\text{Sum of female ages }}}}{{{\text{Total number of female person}}}}$
Sum of female ages $ = f \times 35$
As it is given that a is the average of the total person and total number of person is $100$
a = $\dfrac{{{\text{Sum of male ages + Sum of female ages }}}}{{{\text{Total number of person}}}}$
a = $\dfrac{{m \times 65 + f \times 35}}{{100}}$
Now divide in both numerator and denominator by $5$
$a = \dfrac{{13m + 7f}}{{20}}$
Now as in the option all are given in $\dfrac{{m + f}}{2}$ type so try to convert the above equation in this form
$a = \dfrac{{10m + 10f + 3m - 3f}}{{20}}$
$a = \dfrac{{10m + 10f}}{{20}} + \dfrac{{3m - 3f}}{{20}}$
On solving further we get it as
$a = \dfrac{{m + f}}{2} + \dfrac{3}{{20}}(m - f)$
So if the $m > f$ , $a > \dfrac{{m + f}}{2}$
else if , $m < f$ , $a < \dfrac{{m + f}}{2}$
Hence from the above option C is the correct answer.
Note:
In an average type of question we will take any number for solving this as in this question we take $100$ person in the cricket league we also take $10,20$ etc any number but on choosing $100$ the calculation becomes easier.
In this type of question first see the option as in the option all the data is given in the relation of a , m and f. So only the total average age is given this relation so go through that and try to find out the relation between them.
First let us consider that the number of person in the cricket league is $100$ Use the average formula that is = $\dfrac{{{\text{Sum of ages }}}}{{{\text{Total number of person}}}}$ hence Sum of male ages $ = m \times 65$ and Sum of female ages $ = f \times 35$ from here a = $\dfrac{{m \times 65 + f \times 35}}{{100}}$ now try insert $\dfrac{{m + f}}{2}$ in this equation because all options are given in this form after that compare it with options.
Complete step by step solution:
As we know that the average of any given data is,
= $\dfrac{{{\text{Sum of ages }}}}{{{\text{Total number of person}}}}$
So let us consider that the number of person in the cricket league is $100$ and it is given that the $65$ percent of the leagues members are male
Hence $65$ person are male and $35$ person are female ,
As it is given that m is the average of the male person , and total number of male is $65$
therefore m = $\dfrac{{{\text{Sum of male ages }}}}{{{\text{Total number of male person}}}}$
Sum of male ages $ = m \times 65$
As it is given that f is the average of the female person , and total number of male is $35$
therefore f = $\dfrac{{{\text{Sum of female ages }}}}{{{\text{Total number of female person}}}}$
Sum of female ages $ = f \times 35$
As it is given that a is the average of the total person and total number of person is $100$
a = $\dfrac{{{\text{Sum of male ages + Sum of female ages }}}}{{{\text{Total number of person}}}}$
a = $\dfrac{{m \times 65 + f \times 35}}{{100}}$
Now divide in both numerator and denominator by $5$
$a = \dfrac{{13m + 7f}}{{20}}$
Now as in the option all are given in $\dfrac{{m + f}}{2}$ type so try to convert the above equation in this form
$a = \dfrac{{10m + 10f + 3m - 3f}}{{20}}$
$a = \dfrac{{10m + 10f}}{{20}} + \dfrac{{3m - 3f}}{{20}}$
On solving further we get it as
$a = \dfrac{{m + f}}{2} + \dfrac{3}{{20}}(m - f)$
So if the $m > f$ , $a > \dfrac{{m + f}}{2}$
else if , $m < f$ , $a < \dfrac{{m + f}}{2}$
Hence from the above option C is the correct answer.
Note:
In an average type of question we will take any number for solving this as in this question we take $100$ person in the cricket league we also take $10,20$ etc any number but on choosing $100$ the calculation becomes easier.
In this type of question first see the option as in the option all the data is given in the relation of a , m and f. So only the total average age is given this relation so go through that and try to find out the relation between them.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

