
In a coconut grove (x + 2) tree yields 60 nuts per year, x tree yields 120 nuts per year and (x -2) tree yields 180 nuts per year. If the average yield per year per tree is 100 then find x.
a). 4
b). 3
c). 2
d). 1
Answer
565.5k+ views
Hint: To calculate the value of x, we will use the formula of arithmetic mean of grouped data, that is
Arithmetic mean = $\dfrac{\sum\limits_{i}^{i=n}{{{f}_{i}}{{x}_{i}}}}{\sum\limits_{i}^{i=n}{{{f}_{i}}}}$ , and here ${{f}_{i}}$ is equal to number of trees yielding particular number of nuts and ${{x}_{i}}$ is the number of particular nuts.
Complete step by step answer:
From the question, we can see that there are (x + 2) such coconut trees which 60 nuts per year, there are x trees which yield 120 nuts per year and there are (x - 2) such trees which yield 180 nuts per year.
And, for the grouped data we know that arithmetic mean = $\dfrac{\sum\limits_{i}^{i=n}{{{f}_{i}}{{x}_{i}}}}{\sum\limits_{i}^{i=n}{{{f}_{i}}}}$, and here ${{f}_{i}}$ is equal to number of trees yielding particular number of nuts and ${{x}_{i}}$ is the number of particular nuts.
So, we can say that when ${{f}_{1}}$ = (x + 2), ${{x}_{1}}$ = 60. Similarly, when ${{f}_{2}}$= x, ${{x}_{2}}$= 120 and when ${{f}_{3}}$ = (x - 2), ${{x}_{3}}$= 180.
So, we can say that arithmetic mean = $\dfrac{{{f}_{1}}{{x}_{1}}+{{f}_{2}}{{x}_{2}}+{{f}_{3}}{{x}_{3}}}{{{f}_{1}}+{{f}_{2}}+{{f}_{3}}}$= $\dfrac{\left( x+2 \right)\times 60+x\times 120+\left( x-2 \right)\times 180}{x+2+x+x-2}$
So, arithmetic mean = $\dfrac{360x-240}{3x}$
And, we know that average is nothing but the arithmetic mean.
So, we can say that the average yield per year per tree is equal to $\dfrac{360x-240}{3x}$, but from the question we know that average yield per year per tree is 100.
So, $\dfrac{360x-240}{3x}$ = 100
$\Rightarrow 360x-240=300x$
$\Rightarrow 60x=240$
$\therefore x=4$
So, the correct answer is “Option a”.
Note: Students are required to note that ${{f}_{i}}$ is the frequency of each terms(${{x}_{i}}$) in the data set (i.e. number of times a particular term ${{x}_{i}}$ occur) and they should not get confused among ${{f}_{i}}$ and ${{x}_{i}}$. among about which term will be in the denominator of the arithmetic mean. Most of the students write summation of ${{x}_{i}}$in the denominator of the arithmetic mean formula in place of summation of ${{f}_{i}}$.
Arithmetic mean = $\dfrac{\sum\limits_{i}^{i=n}{{{f}_{i}}{{x}_{i}}}}{\sum\limits_{i}^{i=n}{{{f}_{i}}}}$ , and here ${{f}_{i}}$ is equal to number of trees yielding particular number of nuts and ${{x}_{i}}$ is the number of particular nuts.
Complete step by step answer:
From the question, we can see that there are (x + 2) such coconut trees which 60 nuts per year, there are x trees which yield 120 nuts per year and there are (x - 2) such trees which yield 180 nuts per year.
And, for the grouped data we know that arithmetic mean = $\dfrac{\sum\limits_{i}^{i=n}{{{f}_{i}}{{x}_{i}}}}{\sum\limits_{i}^{i=n}{{{f}_{i}}}}$, and here ${{f}_{i}}$ is equal to number of trees yielding particular number of nuts and ${{x}_{i}}$ is the number of particular nuts.
So, we can say that when ${{f}_{1}}$ = (x + 2), ${{x}_{1}}$ = 60. Similarly, when ${{f}_{2}}$= x, ${{x}_{2}}$= 120 and when ${{f}_{3}}$ = (x - 2), ${{x}_{3}}$= 180.
So, we can say that arithmetic mean = $\dfrac{{{f}_{1}}{{x}_{1}}+{{f}_{2}}{{x}_{2}}+{{f}_{3}}{{x}_{3}}}{{{f}_{1}}+{{f}_{2}}+{{f}_{3}}}$= $\dfrac{\left( x+2 \right)\times 60+x\times 120+\left( x-2 \right)\times 180}{x+2+x+x-2}$
So, arithmetic mean = $\dfrac{360x-240}{3x}$
And, we know that average is nothing but the arithmetic mean.
So, we can say that the average yield per year per tree is equal to $\dfrac{360x-240}{3x}$, but from the question we know that average yield per year per tree is 100.
So, $\dfrac{360x-240}{3x}$ = 100
$\Rightarrow 360x-240=300x$
$\Rightarrow 60x=240$
$\therefore x=4$
So, the correct answer is “Option a”.
Note: Students are required to note that ${{f}_{i}}$ is the frequency of each terms(${{x}_{i}}$) in the data set (i.e. number of times a particular term ${{x}_{i}}$ occur) and they should not get confused among ${{f}_{i}}$ and ${{x}_{i}}$. among about which term will be in the denominator of the arithmetic mean. Most of the students write summation of ${{x}_{i}}$in the denominator of the arithmetic mean formula in place of summation of ${{f}_{i}}$.
Recently Updated Pages
Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Master Class 9 English: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which places in India experience sunrise first and class 9 social science CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Write the 6 fundamental rights of India and explain in detail

Difference Between Plant Cell and Animal Cell

What is the Full Form of ISI and RAW

Golden Revolution is related to AFood production BOil class 9 social science CBSE

