Answer
Verified
429.3k+ views
Hint: We can solve the problem by using the general relations and using the Venn diagram.
We will apply the formula of \[n(H \cup E) = n(H) + n(E) + n(H \cap E)\]. Here, \[H\] means number of students who can speak Hindi and \[E\] means the number of students who can speak English.
Then, using the formula and given information we can find the number of students who can speak both.
Complete step by step answer:
It is given that; the total number of students in the class is \[45\].
The number of students who can speak Hindi is \[22\].
The number of students who can speak English is \[12\].
We have to find the number of students who can speak both Hindi and English.
So, as per the given information
\[n(H \cup E) = 45\]
\[n(H) = 22\]
\[n(E) = 12\]
Let us consider the number of students who can speak both Hindi and English is \[x\] that is \[n(H \cap E) = x\].
We have to find the value of \[n(H \cap E)\].
We know that,
\[ \Rightarrow n(H \cup E) = n(H) + n(E) + n(H \cap E)\]
Substitute the values in the above formula we get,
\[ \Rightarrow 45 = 22 + 12 + x\]
Simplifying we get,
\[ \Rightarrow x = 11\]
Hence, the number of students who can speak both Hindi and English is \[11\].
$\therefore $ The correct answer is option A) \[11\]
Note:
We can solve the sum by using a Venn diagram.
Here, the red shaded part indicates the number of students who can speak Hindi is \[22\].
The blue shaded part indicates the number of students who can speak English is \[12\].
The green shaded part indicates the number of students who can speak both Hindi and English.
The total number of students in the class is \[45\].
We have to find the value of the green shaded part.
So, the value of green-shaded part is
\[45 - (22 + 12) = 11\]
Hence, the number of students who can speak both Hindi and English is \[11\].
We will apply the formula of \[n(H \cup E) = n(H) + n(E) + n(H \cap E)\]. Here, \[H\] means number of students who can speak Hindi and \[E\] means the number of students who can speak English.
Then, using the formula and given information we can find the number of students who can speak both.
Complete step by step answer:
It is given that; the total number of students in the class is \[45\].
The number of students who can speak Hindi is \[22\].
The number of students who can speak English is \[12\].
We have to find the number of students who can speak both Hindi and English.
So, as per the given information
\[n(H \cup E) = 45\]
\[n(H) = 22\]
\[n(E) = 12\]
Let us consider the number of students who can speak both Hindi and English is \[x\] that is \[n(H \cap E) = x\].
We have to find the value of \[n(H \cap E)\].
We know that,
\[ \Rightarrow n(H \cup E) = n(H) + n(E) + n(H \cap E)\]
Substitute the values in the above formula we get,
\[ \Rightarrow 45 = 22 + 12 + x\]
Simplifying we get,
\[ \Rightarrow x = 11\]
Hence, the number of students who can speak both Hindi and English is \[11\].
$\therefore $ The correct answer is option A) \[11\]
Note:
We can solve the sum by using a Venn diagram.
Here, the red shaded part indicates the number of students who can speak Hindi is \[22\].
The blue shaded part indicates the number of students who can speak English is \[12\].
The green shaded part indicates the number of students who can speak both Hindi and English.
The total number of students in the class is \[45\].
We have to find the value of the green shaded part.
So, the value of green-shaded part is
\[45 - (22 + 12) = 11\]
Hence, the number of students who can speak both Hindi and English is \[11\].
Recently Updated Pages
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Advantages and disadvantages of science
Trending doubts
Which are the Top 10 Largest Countries of the World?
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write a letter to the principal requesting him to grant class 10 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
10 examples of evaporation in daily life with explanations