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In a certain code language, if the value of 38+15=66 and 29+36=99, then what is the value of 82+44?
(a) 77
(b) 88
(c) 80
(d) 92

Answer
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Hint: We start solving this problem by writing the number on the right-hand side of the result into the multiplication of two numbers. We then write those numbers as the sum of the digits present on the left-hand side to get the relation between the digits involving the sum for both the given results. We then use that relationship for the result of 82+44 in a similar way to get the required answer.

Complete step-by-step solution
According to the problem, we are given that the values are defined in a certain code language as 38+15=66 and 29+36=99. We need to find the value of 82+44.
Now, we need to find the relation between the three numbers present at 38+15=66.
So, we have 38+15=66.
38+15=11×6.
38+15=(3+8)×(1+5) ---(1).
Now, let us find the relation between the three numbers present in 29+36=99.
29+36=11×9.
29+36=(2+9)×(3+6) ---(2).
From equations (1) and (2), we can see that the sum of two numbers in the form of mn and pq is defined as mn+pq=(m+n)×(p+q).
Let us use this result for finding the value of 82+44.
82+44=(8+2)×(4+4).
82+44=10×8.
82+44=80.
So, we have found the value of 82+44 as 80.
∴ The correct option for the given problem is (c).

Note: We should know that the given set of results can give different answers for a different type of relations performed by the setter of the question. We can also get another result as shown below:
We have 38+15=66.
38+15=36+30.
38+15=(382)+(15×2) ---(3).
Now, we have 29+36=99.
29+36=27+72.
29+36=(292)+(36×2) ---(2).
From equations (1) and (2), we can see that the sum of two numbers in the form of mn and pq is defined as mn+pq=(mn2)+(pq×2).
Let us use this result for finding the value of 82+44.
82+44=(822)+(44×2).
82+44=80+88.
82+44=168.
So, we need to perform different methods to get answers as mentioned in the problems.