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In a battle 70% of the combatants lost one eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs the minimum value of x is: -
A) 10
B) 12
C) 15
D) 5

Answer
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Hint: Here first we will consider the total number of combatants as 100. Then we will find the number of combatants who do not lose any limb and then finally subtract them from the total number of combatants in order to get the number of combatants who lost all the four limbs.

Complete step-by-step answer:
It is given that:
70% of the combatants lost one eye, 80% an ear, 75% an arm, 85% lost a leg
No we have to find the percentage of combatants who lost all four limbs i.e. x%
Let the total number of combatants be 100.
Then, when 70% of them lose one eye implies 30% do not lose any eye.
When 80% of them lose an ear implies 20% do not lose any ear.
When 75% of them lost an arm implies 25% do not lose any arm.
When 85% of them lose a leg implies 15% do not lose any leg.
Hence, the number of combatants who do not lose any of the four limbs are:-
Number of combatants who do not lose any of the four limbs = \[30 + 20 + 25 + 15\]
                                                                                                               = 90 combatants
Now to find the number of combatants who lost all their four limbs we have to subtract the combatants who do not lose any limb from the total number of combatants.
Hence, the number of combatants who lost all their four limbs = \[100 - 90\]
                                                                                                                 = \[10\]
Hence the value of x is 10
Hence the minimum percentage of combatants who lost all four limbs is 10%

Hence option A is correct.

Note: In such questions in which the total number is not given and all other things are given in percentage we usually take the total number to be 100 in order to make calculations easy.