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In a battle 70% of the combatants lost one eye, 80% an ear, 75% an arm, 85% a leg, $x\% $ lost all four limbs the minimum value of x is:-
A) 10
B) 12
C) 15
D) 5

Answer
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Hint:Consider there are a total of 100 combatants in the battle. Then find the combatants that do not lose any eye, similarly find the number of combatants that do not lose any ear, arm and leg.

Complete step-by-step answer:
Given: We have given the percentage of combatants who lost at least one limb which are $70\% $ lost their one eye, $80\% $ lost their an ear, $75\% $ lost their an arm, $85\% $ lost their a leg and we have to find the percentage of combatants who lost all the four limbs.
First, we will consider that there are a total of 100 combatants.
Then, if 70% combatants lost one eye which implies that 30 do not lose any eye.
If 80% combatants lost any ear which implies that 20 do not lose any ear.
If 75% combatants lost any arm which implies that 25 do not lose any arm.
If 85%combatants lost any leg which implies that 15 do not lose any leg.
Now, we will add up the number of combatants which lost at least one limb.
Now, Number of combatants who do not lost any limb \[ = 30 + 20 + 25 + 15 = 90\]
Now, to find the number of combatants who lost their all four limbs, we will subtract the number of combatants from the total which is 100.
Number of combatants who lost all the four limbs is equal to \[100 - 90 = 10\]
Which means the value of $x$ is 10.
Therefore, the minimum percentage of combatants who lost all their 4 limbs is 10%.
Hence the correct option is A.

Note:We will find out the percentage of combatants who lost their all the four limbs by adding the percentage of combatants who did not lose any limb then we will subtract them from the total which is $100\% $.